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lbvjy [14]
3 years ago
14

Quadratic functions. Did I do it right?

Mathematics
1 answer:
patriot [66]3 years ago
6 0

Answer:

1) The graph is opening upwards

2) Axis of symmetry is x=-2

3) Vertex: (-2, 1) minimum y=1

4) y intercept is (0, 9)

5) domain: x|x ∈ R (All real numbers)

6) Range y|y ≥ 1

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35 + 70 = 35(1 + 2)<br> O Yes<br> O No
Sliva [168]

Answer:

Yes

Step-by-step explanation:

Because 35 * 1 is 35 and 35 * 2 is 70

6 0
4 years ago
Read 2 more answers
Find cos theta, tan theta, and csc theta, where is the angle shown in the figure.
guapka [62]
Remember (Soh) (Cah) (Toa). CSC is just the inverse of sine.

8 0
3 years ago
Me ajudem com a 3º questão
Alisiya [41]

I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.

10 = \dfrac{n(n-3)}{2}

20 = n^2 - 3n

n^2 - 3n - 20 = 0

Answer: n² - 3n - 20 = 0

That doesn't factor so there is no integer n solution.

That means there are no polygons with 10 diagonals.

n = \frac 1 2(3 \pm \sqrt{89})

7 0
3 years ago
An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 4385 feet and Plane B is at an altitude
Fantom [35]

Answer:

60 seconds, 7715 feet

Step-by-step explanation:

Plane A and B start out 615 feet apart, and we find this by subtracting the height of plane A from plane B, getting 5000-4385=615. Now we have to find how many more feet of altitude plane A is gaining per second over plane B.

To find this we subtract 45.25 from 55.5 and get 10.25 feet per second. Now to find out how many seconds until they'll be at the same altitude we simply divide 615 by 10.25, getting 60 seconds.

For the second part, to find the altitude at this point, we simply multiply the altitude gain of one of the planes per second by the time of 60 seconds to get how much altitude they gained over that time, and add it to the starting altitude. Doing this with plane B we get 45.25*60=2715, and we add that to 5000 to get the final answer of 7715.

4 0
3 years ago
Jerry played with 333 friends today, all at different times. He played with Tommy for 1\dfrac{7}{8}1 8 7 ​ 1, start fraction, 7,
Mars2501 [29]

Answer:

8 1/8 hours

Step-by-step explanation:

Jerry played with 3 friends today, all at different times.

Tommy = 1 7/8 hours

Nathan = 1 3/4 hours

Chris = 3 3/2 hours

How many hours did Jerry play with his 3 friends today?

Number of hours Jerry play with his 3 friends today = 1 7/8 + 1 3/4 + 3 3/2

= 15/8 + 7/4 + 9/2

= (15+14+36)/8

= 65/8

= 8 1/8 hours

5 0
3 years ago
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