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ANTONII [103]
3 years ago
13

After a recrystallization, a pure substance will ideally appear as a network of __________. If this is not the case, it may be w

orthwhile to reheat the flask and allow the contents to cool more _________
Chemistry
1 answer:
Stells [14]3 years ago
4 0

Answer:

Large crystals

Slowly

Explanation:

Recrystallization is a procedure used to purify an impure compound in a solvent. The concept used here is that the solubility of most of the solids increases with increase in temperature.

Recrystallization is also called as method of fractional crystallization.

After a recrystallization, a pure substance will ideally appear as a network of <u>large crystals</u>. If this is not the case, it may be worthwhile to reheat the flask and allow the contents to cool more <u>slowly</u>.

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Three positive charges lie on the x axis: q1 = 1 × 10−8 C at x1 = 1 cm, q2 = 2 × 10−8 C at x2 = 2 cm, and q3 = 3 × 10−8 C at x3
NARA [144]

Answer: Option (4) is the correct answer.

Explanation:

Relation between potential energy and charge is as follows.

                 U = \frac{1}{4 \pi \epsilon_{o}}[\frac{q_{1}q_{2}}{r_{12}} + \frac{q_{2}q_{3}}{r_{23}} + \frac{q_{3}q_{1}}{r_{31}}]

As it is given that q_{1} = 1 \times 10^{-8} C, q_{2} = 2 \times 10^{-8} C, and q_{3} = 3 \times 10^{-8} C.

        Distance between the charges = 1 cm = 1 \times 10^{-2} m  (as 1 cm = 0.01 m)

Hence, putting these given values into the above formula as follows.

                 U = \frac{1}{4 \pi \epsilon_{o}}[\frac{q_{1}q_{2}}{r_{12}} + \frac{q_{2}q_{3}}{r_{23}} + \frac{q_{3}q_{1}}{r_{31}}]

            = 9 \times 10^{9} [\frac{1 \times 10^{-8} \times 2 \times 10^{-8}}{10^{-2}} + \frac{2 \times 10^{-8} \times 3 \times 10^{-8}}{10^{-2}} + \frac{3 \times 10^{-8} \times 1 \times 10^{-8}}{10^{-2}}]    

            = 9 \times 10^{9} [2 + 6 + 1.5]

            = 85.5 \times 10^{-5} J

            = 0.00085 J

Thus, we can conclude that the potential energy of this arrangement, relative to the potential energy for infinite separation, is about 0.00085 J.              

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Explanation:

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