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2 years ago

I will give brainliest to correct answer - no links

Chemistry

2 answers:

WINSTONCH [101]2 years ago

6 0

Answer:

C - 23cm

Explanation:

Lostsunrise [7]2 years ago

5 0

Answer:

Explanation:

cuz si senor.

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A student uses a dye to change the colour of his tee-shirt. he fills a metal bucket with water. When the bucket is heated, what

Tanya [424]

Answer:

The particles begin to vibrate faster and more.

Explanation:

Adding heat to matter increases the energy, thus creating more movement. Eventually, the bucket will melt, turning to a liquid. While it is a sold, it still has particle movement, just not enough to break volume or shape.

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2 years ago

The second electron shell of an atom can hold a maximum of ______ electron(s).

lawyer [7]

Can hold max of 8 electrons

5 0

2 years ago

hi, 100 points, , will also mark brainly-ist (what's the boiling point of water) ((you don't need to answer that))

BaLLatris [955]

Answer:

212 degrees F, and 100 degrees C.

Explanation:

If the temperature is held constant (which requires some heat input, since evaporation cools things) the liquid will all evaporate. If the temperature is much above 212 F, the water will boil. That means that it wont just evaporate from the surface but will form vapor bubbles, which then grow, inside the liquid itself. :)

6 0

2 years ago

Compare the number of valence electrons in an atom of oxygen, o, with the number of valence electrons in an atom of selenium, se

Fiesta28 [93]

Oxygen and selenium both have 6 valence electrons. They're in the same group hope this helps

4 0

2 years ago

For the following reaction, 7.53 grams of benzene (C6H6) are allowed to react with 8.33 grams of oxygen gas. benzene (C6H6) (l)

juin [17]

Answer:

The maximum amount of CO2 that can be formed is 9.15 grams CO2

O2 is the limiting reactant

There will remain 4.82 grams of benzene

Explanation:

Step 1: Data given

Mass of benzene = 7.53 grams

Mass of oxygen gas = 8.33 grams

Molar mass of benzene = 78.11 g/mol

Molar mass oxygen gas = 32.00 g/mol

Step 2: The balanced equation

2C6H6 + 15O2 → 12CO2 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles C6H6 = 7.53 grams / 78.11 g/mol

Moles C6H6 = 0.0964 moles

Moles O2 = 8.33 grams / 32.00 g/mol

Moles O2 = 0.2603 moles

Step 4: Calculate the limiting reactant

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.2603 moles). Benzene is in excess. there will react 2/15 * 0.2603 = 0.0347 moles

There will remain 0.0964 - 0.0347 = 0.0617 moles benzene

This is 0.0617 moles * 78.11 g/mol = 4.82 grams benzene

Step 5: Calculate moles CO2

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

For 0.2603 moles O2 we'll have 12/15 * 0.2603 = 0.208 moles CO2

Step 6: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.208 moles * 44.01 g/mol

Mass CO2 = 9.15 grams

4 0

3 years ago