Answer:
0.48atm
Explanation:
Firstly, we need to know the mole ratio of the oxygen gas involved. To do this, we simply place the number of moles of the oxygen over the sum of both gases.
This would be 3/(3+7) = 0.3
Now, to get the partial pressure contributed by the oxygen gas, we simply multiply the 0.3 by the total pressure
Hence, the partial pressure of oxygen = the mole fraction of oxygen * the total pressure.
= 0.3 * 1.6 = 0.48atm
Answer:
The different forms of an element based on the number of neutrons in the nucleus are called "isotopes." Carbon-12 is only one isotope of the element carbon, with 6 protons and 6 neutrons. There are also carbon-13, with 6 protons and 7 neutrons, and carbon-14, with 6 protons and 8 neutrons.
Explanation:
Oxygen = 16
Iron = 55.8
16 x 27.6% = 4.4 /4 = 1.1
55.8 x 72.4% = 40.4 /4 = 10.1
1 oxygen and 10 iron, so Fe10 O
Answer:
Use E = h*c / lambda, where h is Planck's constant, c is the speed of light, and lambda is the wavelength.
E = (6.626 * 10^-34 J*s x 3.00 * 10^8 m/s) / (1*10^-6 m) = 1.99 * 10^-19 J
Explanation:
Answer:
Kc=13.61
Explanation:
A chemical equilibrium is the situation in which the ratio between the amounts of reagents and products in a chemical reaction remains constant over time.
The equilibrium constant (Kc) is useful for the study of chemical equilibrium, being a constant that indicates whether the reaction is favored to the formation of products or to the formation of reactants.
Being:
aA + bB ⇔ cC + dD
where a, b, c, d are the stoichiometric coefficients of the reaction and A, B, C, D are the symbols or formulas of the different substances involved
Then:
![Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%2A%5BD%5D%5E%7Bd%7D%20%7D%7B%5BA%5D%5E%7Ba%7D%20%2A%5BB%5D%5E%7Bb%7D%20%7D)
where [] is the Molar concentration of each of the substances in equilibrium.
In this case, you know: 2 SO₂(g) +O₂(g)⇌2 SO₃(g)
So: ![Kc=\frac{[SO_{3} ]^{2} }{[SO_{2}] ^{2} *[O_{2} ]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BSO_%7B3%7D%20%5D%5E%7B2%7D%20%7D%7B%5BSO_%7B2%7D%5D%20%5E%7B2%7D%20%2A%5BO_%7B2%7D%20%5D%7D)
Being: [SO2]=0.48 M, [O2]=0.40 M, and [SO3]=1.12 M
![Kc=\frac{[1.12]^{2} }{[0.48] ^{2} *[0.40 ]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5B1.12%5D%5E%7B2%7D%20%7D%7B%5B0.48%5D%20%5E%7B2%7D%20%2A%5B0.40%20%5D%7D)
Kc=13.61