Question

Naming Compounds Test Review Practice Name the following ionic compounds: NH4Cl _____________________________________ Fe(NO3)3 _____________________________________ TiBr3 _____________________________________ Cu3P _____________________________________ SnSe2 _____________________________________ GaAs _____________________________________ Pb(SO4)2 _____________________________________ Be(HCO3)2 _____________________________________ Mn2(SO3)3 _____________________________________ Al(CN)3 _____________________________________

Answer 1

Answer :

The name of $NH_4Cl$ is ammonium chloride.

The name of $Fe(NO_3)_3$ is iron(III) nitrate.

The name of $TiBr_3$ is titanium(III) bromide.

The name of $Cu_3P$ is copper(I) phosphide.

The name of $SnSe_2$ is tin(IV) selenide.

The name of $GaAs$ is gallium arsenide.

The name of $Pb(SO_4)_2$ is lead(IV) sulfate.

The name of $Be(HCO_3)_2$ is beryllium hydrogen carbonate.

The name of $Mn_2(SO_3)_3$ is manganese(III) sulfite.

The name of $Al(CN)_3$ is aluminium cyanide.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) $NH_4Cl$

It is an ionic compound because it is formed by the combination of one polyatomic cation (ammonium ion) and anion (chloride ion). The charge on ammonium ion is (+1) and the the charge on chloride ion is (-1).

Thus, the name of $NH_4Cl$ is ammonium chloride.

(b) $Fe(NO_3)_3$

It is an ionic compound because it is formed by the combination of one polyatomic anion (nitrate ion) and cation (iron ion). The charge on iron ion is (+3) and the the charge on nitrate ion is (-1).

Thus, the name of $Fe(NO_3)_3$ is iron(III) nitrate.

(c) $TiBr_3$

It is an ionic compound because it is formed by the combination of titanium cation and bromide anion. The charge on titanium is (+3) and the the charge on bromide ion is (-1).

Thus, the name of $TiBr_3$ is titanium(III) bromide.

(d) $Cu_3P$

It is an ionic compound because it is formed by the combination of copper cation and phosphorous anion. The charge on copper is (+1) and the the charge on phosphorous ion is (-3).

Thus, the name of $Cu_3P$ is copper(I) phosphide.

(e) $SnSe_2$

It is an ionic compound because it is formed by the combination of tin cation and selenium anion. The charge on tin is (+4) and the the charge on selenium ion is (-2).

Thus, the name of $SnSe_2$ is tin(IV) selenide.

(f) $GaAs$

It is an ionic compound because it is formed by the combination of gallium cation and arsenic anion. The charge on gallium is (+3) and the the charge on arsenic ion is (-3).

Thus, the name of $GaAs$ is gallium arsenide.

(g) $Pb(SO_4)_2$

It is an ionic compound because it is formed by the combination of one polyatomic anion (sulfate ion) and cation (lead ion). The charge on lead ion is (+4) and the the charge on sulfate ion is (-2).

Thus, the name of $Pb(SO_4)_2$ is lead(IV) sulfate.

(h) $Be(HCO_3)_2$

It is an ionic compound because it is formed by the combination of one polyatomic anion (hydrogen carbonate ion) and cation (beryllium ion). The charge on beryllium ion is (+2) and the the charge on hydrogen carbonate ion is (-1).

Thus, the name of $Be(HCO_3)_2$ is beryllium hydrogen carbonate.

(i) $Mn_2(SO_3)_3$

It is an ionic compound because it is formed by the combination of one polyatomic anion (sulfite ion) and cation (manganese ion). The charge on manganese ion is (+3) and the the charge on sulfite ion is (-2).

Thus, the name of $Mn_2(SO_3)_3$ is manganese(III) sulfite.

(j) $Al(CN)_3$

It is an ionic compound because it is formed by the combination of one polyatomic anion (cyanide ion) and cation (aluminium ion). The charge on aluminium ion is (+3) and the the charge on cyanide ion is (-1).

Thus, the name of $Al(CN)_3$ is aluminium cyanide.