All categories

3 years ago

How does sunlight hits earths surface closer to the poles?

Chemistry

1 answer:

borishaifa [10]3 years ago

3 0

Answer:

When the sun's rays strike Earth's surface near the equator, the incoming solar radiation is more direct (nearly perpendicular or closer to a 90˚ angle). Therefore, the solar radiation is concentrated over a smaller surface area, causing warmer temperatures.

Explanation:

You might be interested in

Nonferrous alloys do not contain a. copper. b. brass. c. gold. d. iron.

marin [14]

Nonferrous alloys do not contain iron as the name suggests. Ferrous is the latin word for iron. These alloys use precious metals such as gold, silver, platinum and other metals like copper, aluminum, lead, zinc and even alloys like brass. Answer is D.

6 0

4 years ago

When an equation is used to calculate the amount of product that will form during a reaction, then the value obtained is called

bekas [8.4K]

This would be the theoretical yield. This is the amount of product that should be obtained in the end of a reaction, given that none of the reactants are wasted in the creation of the product. This is unlikely to be exactly obtained, however, due to waste products being formed in the process.

6 0

3 years ago

Read 2 more answers

A compound has been shown to contain 14.5 percent hydrogen and 85.5 percent carbon by mass.

Sedaia [141]

Answer:

Option d. Its empirical formula is CH₂.

Explanation:

The percent composition of the compound allow you to calculate the empirical formula of the compound but is not enough to calculate either the molar mass or the molecular formula. So, since now you can discard options b. and c.

Telling that it is a hydrocarbon (option e.) is true but very vague compared with finding the empirical formula. So, you can also discard the option e.

The fact that the product has a triple bond cannot be concluded from the percent composition, you should find the molecular formula to assert whether it contains or not a triple bond. So, you could discard option a., which lets you only with choice d.

Let us find the empirical formula to be certain that it is CH₂.

1. First, assume a basis of 100 g of compound:

H: 14.5% × 100 g = 14.0 g

C: 85.5% × 100 g = 85.5 g

2. Divide each element by its atomic mass to find number of moles:

H: 14.0 g / 1.008 g/mol = 14.38 mol

C: 85.5 g / 12.011 g/mol = 7.12 mol

3. Divide both amounts by the smallest number, to find the mole ratio:

H: 14.38 mol / 7.12 mol ≈ 2
C: 7.12 mol / 7.12 mol = 1.

Hence, the ratio is 2:1 and the empirical formula is CH₂.

7 0

3 years ago

Organisms such as grass and lichens are classified as

mash [69]

I think the answer is producers

I hope that helped and have a nice day!! (:

3 0

3 years ago

2.A calibration curve requires the preparation of a set of known concentrations of CV, which are usually prepared by dieting a s

Aleks04 [339]

Answer:

In order to prepare 10 mL, 5 μM; 2 mL of the 25 μM stock solution will be taken and diluted with water up to 10 mL mark.

In order to prepare 10 mL, 10 μM; 4 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.

In order to prepare 10 mL, 15 μM; 6 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.

In order to prepare 10 mL, 20 μM; 8 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.

Explanation:

Using the dilution equation:

no of moles before dilution = no of moles after dilution.

Molarity x volume (initial)= Molarity x volume (final).

In order to prepare 10 mL, 5 μM from 25 μM solution,

Final molarity = 5 μM, final volume = 10 mL, initial molarity = 25 μM, initial volume = ?

25 x initial volume = 5 x 10

Initial volume = 50/25

= 2 mL

2 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.

In order to prepare 10 mL, 10 μM from 25 μM stock,

25 x initial volume = 10 x 10

Initial volume = 100/25 = 4 mL

4 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.

In order to prepare 10 mL, 15 μM from 25 μM stock,

25 x initial volume = 15 x 10

initial volume = 150/25 = 6 mL

6 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.

In order to prepare 10 mL, 20 μM from 25 μM stock,

25 x initial volume = 20 x 10

initial volume = 200/25 = 8 mL

8 mL of the 25 μM stock solution will be taken and diluted up to 10 mL mark.

6 0

3 years ago