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Lera25 [3.4K]
3 years ago
13

Cuanto es en total de 6000x1

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0

Answer:

make it in english pliss

Step-by-step explanation:

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Firewood can be sold in cords. the wood is cut into equal lengths and stacked evenly in a rack. which geometric shape can be use
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To estimate the volume of the chord of wood, since the wood exists cut into equal lengths and stacked evenly in a rack then we can use a cylinder as a model.

<h3>What is a cylinder?</h3>

In mathematics, a cylinder exists as a three-dimensional solid that holds two parallel bases joined by a curved surface, at a fixed distance. These bases exist normally circular (like a circle) and the center of the two bases exists joined by a line segment, which exists named the axis.

A cylinder exists as a closed solid that contains two parallel circular bases joined by a curved surface.

To calculate the volume of the chord of wood, since the wood exists cut into equal lengths and stacked evenly in a rack then we can use a cylinder as a model.

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2 years ago
Quadrilateral ABCD?<br>​
Mashutka [201]

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = \sqrt{(7 - 2)^{2} + (4 - 4)^{2}  }

⇒ AD = \sqrt{5^{2} }

⇒ AD = 5

DC = \sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }

⇒ DC = \sqrt{5^{2} }

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = \sqrt{(-2 - 2)^{2}  + (-5 - 4)^{2} }

⇒ AB = \sqrt{(-4)^{2} + (-9)^{2}  }

⇒ AB = \sqrt{16 + 81}

⇒ AB = \sqrt{97}

BC = \sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2}  }

⇒ BC = \sqrt{9^{2}  + 4^{2} }

⇒ BC = \sqrt{81 + 16}

⇒ BC = \sqrt{97}

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

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6 0
1 year ago
3x^2 -5x -2=0
Kipish [7]

Answer:

Step-by-step explanation:

1. Find two numbers that add to make the coefficient of x (in this case, -5) and that multiply to make the constant term multiplied by the coefficient of x^2 (in this case, -2 x 3 = -6)

Two numbers that work are -6 and +1

-6 x +1 = -6

-6 + -1 = -5

2. Split the middle term into the two numbers that you found.

3x^2 -6x +x -2 = 0

I've put the -6 on the left side because in our next step, when we factorise, it will be easier than having the numbers the other way around.

3. Factorise the left side by taking out common factors from each pair. The pairs I'm talking about here are '3x^2 and -6x', and 'x and -2'

3x (x-2) +1 (x-2) = 0

4. You now have two numbers both being multiplied by the term x-2. We can rearrange this equation to give us two brackets being multiplied by each other.

(3x + 1) (x-2) = 0

5. According to the Null Factor Law, if two terms are multiplied together and the result is 0, then one of those terms must be 0. Make both terms equal to 0 and solve each for x.

3x + 1 = 0              x-2 = 0

3x = -1                   x = 2

x = -1/3

6. The solutions to this equation are x = 2 and x = -1/3

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