Ask question

Ask question

All categories

3 years ago

13

The model represents the equation 3x – 2 < 4. What is the solution for this inequality? x < 2 x < 6 x < -2 x < -3

2 answers:

Oksana_A [137]3 years ago

6 0

Answer:

the answer is x<2

Step-by-step explanation:

lol

valkas [14]3 years ago

4 0

Answer:

x<2

Step-by-step explanation:

3x-2+2<4-+2

3/3x<6/3

x<2

ur welcome ;)

You might be interested in

On a map, 2.5 inches represents 52 miles. What is the actual distance represented by 5 inches on the map?

nikklg [1K]

Answer:

104 miles

Step-by-step explanation:

52/2.5 = 20.8

20.8 miles = 1 inch

20.8 x 5

104 miles = 5 inches

7 0

3 years ago

Read 2 more answers

2.5 m<br> 9 m<br> 1<br> 24 m<br> Work out the perimeter.

deff fn [24]

Step-by-step explanation:

thirty six point five(36.5)

7 0

2 years ago

Read 2 more answers

-1 + 14x = 12x + 17 Whats the answer ? what is x

Finger [1]

Answer:

x= 9

Step-by-step explanation:

Move the terms -> -1=14x = -12x + 16

Find out the sum -> 2x=17+1

Divide both by the equation by two -> 2x=18 x=9

Final answer: x=9

8 0

3 years ago

Yesterday, 4/7 of the 210 students in a contest gave their speeches. How many students gave their speeches?

Elenna [48]

Answer:

120.

Step-by-step explanation:

210 * 4/7

= 30 * 4

= 120.

6 0

3 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago