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2 years ago

What is an equation of the line that passes through the points ( 0,-7) and ( 5, -1)

Mathematics

1 answer:

tresset_1 [31]2 years ago

7 0

Answer:

y = 5/6x - 5.167

y = 5/6x - 31/6

Step-by-step explanation:

The equation of a line

y = mx + c

Step 1: find the slope

m = y2 - y1 / x2 - x1

Given points

( 0 , -7) ( 5 , -1)

x1 = 0

y1 = -7

x2 = 5

y2 = -1

Insert the values into the equation

m = -1 - (-7) / 5 - 0

m = -1 + 7 / 5

m = 6/5

y = 6/5x + c

Step 2: sub any of the two points given into the equation

y = 5/6x + c

( 5 , -1)

x = 5

y = -1

-1 = 5/6(5) + c

-1 = 5*5/6 + c

-1 = 25/6 + c.

c = -1 - 25/6

LCM = 6

c = -6 - 25 / 6

c = -31/6

c = -5.167

Step 3: sub c into the equation

y = 5/6x + c

y = 5/6x - 31/6

y = 5/6x - 5.167

The equation of the line is

y = 5/6x - 5.167

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What is the tenth term in the sequence 9, 13, 17, 21, 25…?

Zinaida [17]

Answer:

Step-by-step explanation:

9, 13, 17, 21, 25

We are adding 4 each time

9+4 = 13

13+4 =17

17+4 = 21

The common difference =4

a1 = 9

The formula is

an = a1+d(n-1) where n is the term number

an = 9+4(n-1)

We want the 10th term

a10 = 9+4(10-1)

= 9+4(9)

= 9+36

= 45

6 0

2 years ago

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n)=-6+(n-1)(1/5) A)-6,-5 1/5,

scoundrel [369]

Step-by-step explanation:

An arithmetic sequence is given by relation as follows :

$A(n)=-6+(n-1)\dfrac{1}{5}$

For the first term, put n = 1. So,

$A(1)=-6+(1-1)\dfrac{1}{5}\\\\A(1)=-6$

For fourth term, put n = 4. So,

$A(4)=-6+(4-1)\dfrac{1}{5}\\\\A(4)=\dfrac{-27}{5}\\\\A(4)=-5\dfrac{2}{5}$

For tenth term, put n = 10. So,

$A(10)=-6+(10-1)\dfrac{1}{5}\\\\A(10)=-6+\dfrac{9}{5}\\\\A(10)=\dfrac{-21}{5}\\\\A(10)=-4\dfrac{1}{5}$

Hence, the correct option is (C).

7 0

3 years ago

What can you conclude from the box-and-whisker plot?

muminat

Answer:

that it is a cat :')

Step-by-step explanation:

remember, whisker = cat

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2 years ago

Regular hexagon ABCDEF has vertices at A(4, 4!3), B(8, 4!3), C(10, 2!3), D(8, 0), E(4, 0) and F(2, 2!3).

marissa [1.9K]

Since the given hexagon is a regular hexagon all it's sides will be of equal length. Now, we know that the Area of any regular hexagon is given by:

$A=\frac{3\sqrt{3}}{2} a^2$

Where $A$ is the area of the regular hexagon

$a$ is the side length of the regular hexagon

Also, it's Perimeter is given by:

$P=6a$

Thus, all that we need to do is to find the side length of any one of the sides and to do that let us have a look at at the data of vertices points given and find out which points are definitely adjacent to each other and are also easy to calculate.

A quick search will yield that D(8, 0) and E(4, 0) are definitely adjacent to each other.

Please check the attached file here for a better understanding of the diagram of the original regular hexagon. Points D and E indeed are adjacent to each other.

Let us now find the distance between the points D and E using the distance formula which is as:

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Where $d$ is the distance.

$(x_1,y_1)$ and $(x_2,y_2)$ are the coordinates of points D and E respectively. (please note that interchanging the values of the coordinates will not alter the distance $d$ )