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Fed [463]
3 years ago
15

gwen and her brother max had 5 one-dollar bills 6 quarters and 8 dime what is the total of money had gwen and her brother earned

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0
7 dollars and 30 cents becuse 4 wuarters equals 1 dollar plus the 5 other equals 6 dollars and then you have 2 quarters left which equals 6 dollars and 50 cents plus the 8 dimes/80 cents and 6 dollars and 50 cents plus 80 cents equals 7 dollars and 30 cents
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Help this is due soon..
WARRIOR [948]

Answer:

y is skipping by 12 each time

Step-by-step explanation:

41+12=53

53+12= 65

65+12=77

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7 0
3 years ago
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Write each expression in exponential form and find its value 1/6*1/6*1/6*1/6
olga55 [171]

Answer:

1/6^4.

Step-by-step explanation:

Multiply denominators.

6*6*6*6 = 1,296

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3 0
3 years ago
A circle has diameter of 8 feet.
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2 years ago
The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards (according to GolfWeek). Assume th
Usimov [2.4K]

Answer:

a) f(x) = \frac{1}{25.9}

b) 0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

P(X < x) = \frac{x - a}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

The probability density function of the uniform distribution is:

f(x) = \frac{1}{b-a}

The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.

This means that a = 284.7, b = 310.6.

a. Give a mathematical expression for the probability density function of driving distance.

f(x) = \frac{1}{b-a} = \frac{1}{310.6-284.7} = \frac{1}{25.9}

b. What is the probability the driving distance for one of these golfers is less than 290 yards?

P(X < 290) = \frac{290 - 284.7}{310.6-284.7} = 0.2046

0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards

3 0
2 years ago
I NEED THIS ASAP!!!!!!!!
drek231 [11]
I know you need this bbc
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3 years ago
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