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icang [17]
3 years ago
15

How many solutions does the equation 3x2-1=4x have

Mathematics
1 answer:
dedylja [7]3 years ago
4 0

Answer:

Being a quadratic equation, this will have two solutions

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How to find all real solutions
AlladinOne [14]
\bf \sqrt{\sqrt{x-5}+x}=5\leftarrow \textit{squaring both sides}
\\\\
\sqrt{x-5}+x=25\implies \sqrt{x-5}=25-x\leftarrow \textit{squaring both sides}
\\\\
x-5=(25-x)^2\implies x-5=625-50x+x^2
\\\\
0=x^2-51x+630\implies 0=(x-30)(x-21)

and surely you'd know what the roots are

7 0
3 years ago
Please help me , I don’t understand :(
Yuri [45]

Answer:

A. 1.4 times

Step-by-step explanation:

The factor in this exponential function is 1.4.

Please see the attachment.

7 0
3 years ago
The measure of ∠A is 35° more than three times the measure of ∠B. The sum of their measures is 135°. Find m ∠A and m ∠B
Margaret [11]
A is 110 degrees and B is 25
8 0
3 years ago
Solve the equation 4(x-5)=2x-14
Ganezh [65]
4x-20=2x-14
-2x. -2x
2x-20=14
+20 +20
2x= 34
— —
2 2
X=17



Therefore x=17
5 0
4 years ago
Read 2 more answers
Csc2theta=csctheta/2costheta<br><br>Can you help verify the identity
Yakvenalex [24]

csc(2x) = csc(x)/(2cos(x))

1/(sin(2x)) = csc(x)/(2cos(x))

1/(2*sin(x)*cos(x)) = csc(x)/(2cos(x))

(1/sin(x))*1/(2*cos(x)) = csc(x)/(2cos(x))

csc(x)*1/(2*cos(x)) = csc(x)/(2cos(x))

csc(x)/(2*cos(x)) = csc(x)/(2cos(x))

The identity is confirmed. Notice how I only altered the left hand side (LHS) keeping the right hand side (RHS) the same each time.

7 0
3 years ago
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