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zlopas [31]
3 years ago
6

Solve this answer 2/3 + 4/6 ​

Mathematics
1 answer:
Colt1911 [192]3 years ago
4 0

Step 1

Now we need to make our denominators match.

6 goes into 3 evenly, so we only need to multiply one term to get a common denominator.

Multiply 2 by 2, and get 4, then we multiply 3 by 2 and get 6.

We now have a new problem, that looks like this:  4/6+4/6

Step 2

Since our denominators match, we can add the numerators.

4 + 4 = 8

That gives us the sum, which is 8/6

Step 3

Now, do we need to simplify this fraction?

First, we attempt to divide it by 2...

Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:

8/6÷ 2 = 4/3

Let's try dividing by that again...

Nope! So now we try the next greatest prime number, 3...

Nope! So now we try the next greatest prime number, 5...

No good. 5 is larger than 4. So we're done reducing.

There you have it! Here's the final answer to 2/3 + 4/6

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4 years ago
In triangle ABC, AB = 7, AC = 15, and the length of median AM is 10. Find the area of triangle ABC.
steposvetlana [31]

Answer:

  42

Step-by-step explanation:

We can make use of Heron's formula for the area of the triangle. Let x represent half the length of BC:

  MB = MC = x

Then the perimeter of ΔAMB is ...

  p1 = 7 + 10 + x

and the value used in Heron's formula, the semi-perimeter is ...

  s1 = (17+x)/2

The square of the area of ΔAMB is then ...

  A1² = s1·(s1 -x)·(s1 -10)·(s1 -7) = (-1/16)(x^4 -298x^2 +2601)

Similarly, the square of the area of ΔABC is ...

  A2² = s2·(s2 -x)·(s2 -10)·(s2 -15) = (-1/16)(x^4 -650x^2 +15625)

We want these two triangle areas to be the same, so we can solve for the value of x that makes it so.

  A1² - A2² = 0 = (-1/16)((x^4 -298x^2 +2601) -(x^4 -650x^2 +15625))

  352x^2 -13024 = 0 . . . . multiply by -16 and collect terms

  x^2 -37 = 0 . . . . . . . . . . . divide by 352

  x^2 = 37 . . . . . this is as far as we need to take it in order to find the area.

Substituting the value for x^2 into the expression for A1², we get ...

  A1² = (-1/16)((x^2 -298)x^2 +2601) = (-1/16)((37 -298)37 +2601) = 441

So, the area of ΔAMB is √441 = 21 square units. The area of ΔAMC is the same, so the area of ΔABC is ...

  area(ΔABC) = 2×area(ΔAMB) = 2×21 units²

  area(ΔABC) = 42 units²

_____

<em>Addendum to the answer</em>

After thinking about this a little more, I realized the area is that of half a parallelogram with AB and AC as two sides and AM as half the diagonal. In other words, the area is the same as that of a triangle with sides 7, 15, and 2×10=20. A single straightforward application of Heron's formula gives the area as ...

  A = √(21(21-7)(21-15)(21-20)) = √(21(14)(6)) = 42

8 0
3 years ago
Find the value of x.
Triss [41]

Answer:

D

Step-by-step explanation:

The midsegment AC is half the sum of the parallel bases, that is

AC = \frac{DF+EB}{2} , then

x = \frac{13+9}{2} = \frac{22}{2} = 11 → D

6 0
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alexgriva [62]

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It may be 834.5m².........…………

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Answer:

the answer to this question is 38degrees

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