Answer:
The possible measures of the midsegment are <u>32 units and 212 units</u>.
Step-by-step explanation:
Given:
A triangle PQR with the midsegment made by sides PQ and PR has length equal to and the base length QR opposite to the midsegment is .
From midsegment theorem, we know that, the midsegment is a line parallel to the base opposite to it and half the length of the base length.
Therefore, Midsegment = Base length QR
Now, midsegment can be calculated using the values of 'x'.
First, plug in -1 for 'x'. This gives,
Now, plug in 4 for 'x'. This gives,
Therefore, the possible measures of the midsegment are 32 units and 212 units
Answer:
Answer:
(x+6)(x+2)=60
expand
x^2+6x+2x+12=60
x^2+8x+12=60
minus 60 both sides
x^2+8x-48=0
factor
what multiplies to -48 and adds to 8
-4 and 12
(x-4)(x+12)=0
set each to zero
x-4=0
x=4
x+12=0
x=-12
x=4 or -12
Step-by-step explanation: