Plzzzzzzz help ppllz

GUYS PLS HELPPP ME!!!!

Alik [6]

It’s C I’m 60% sure

4 0

3 years ago

Read 2 more answers

Two whole numbers have a least common multiple (LCM) of 40.

emmasim [6.3K]

Answer:

10 and 8

Step-by-step explanation:

Case 1:

20 and 2

20 = 2^2 x 5

2 = 2^1

=> LCM = 2^2 x 5 = 20 (not 40)

=> Incorrect pair of numbers

Case 2:

10 and 8

10 = 2 x 5

8 = 2^3

=> LCM = 2^3 x 5 = 40

=> GCF = 2

=> Correct pair of numbers

Case 3:

10 and 4

10 = 2 x 5

4 = 2^2

=> LCM = 2^2 x 5 = 20 (not 40)

=> Incorrect pair of numbers

Case 4:

8 and 5

8 = 2^3

5 = 5 x 1

=> GCF = 1 (not 2)

=> Incorrect pair of numbers

Hope this helps!

:)

5 0

3 years ago

Read 2 more answers

Are x = -4 and x = 6 solutions to 5x + 7 < 22? TRUE OR FALSE

DochEvi [55]

Answer:

x=-4 is true, x=6 is not

Step-by-step explanation:

5x + 7 < 22

Plug in our X values

5(-4) + 7 < 22 ?

solve

-20 + 7 < 22

-13 < 22 ?

x=-4 is true.

Repeat steps from ^

5(6) + 7 < 22

30 + 7 < 22

37 < 22 ?

x=6 is not true.

Hope this helped

4 0

3 years ago

Read 2 more answers

the school cafeteria sells two kinds of wraps: vegetarian and chicken. the vegetarian wraps costs $1.00 and the chicken wrap cos

artcher [175]

Help on my most recent question

3 0

3 years ago

The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (x) after x years is given by:

$f(x) = 0.69\cdot(1.03)^{x}$

After x = 0 years, the price of product A is:

$f(0) = 0.69\cdot(1.03)^{0}=0.69$

After x = 1 years, the price of product A is:

$f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)$

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after x = 2 years, the price of product A is:

$f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)$

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t) Price [f (t)]

1 10,100

2 10,201

3 10,303.01

4 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%$

Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%$

Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%$

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0

3 years ago