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vova2212 [387]
3 years ago
14

How many atoms of each element are present in

Chemistry
1 answer:
viva [34]3 years ago
4 0

Answer:

Three lithium and one nitrogen atoms

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4 years ago
What is the electron configuration for vanadium (V)? The Periodic Table A. 1s22s22p63s23p64s24d3 B. 1s22s22p63s23p63d5 C. 1s22s2
kramer

The electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3 (option D).

<h3>What is electronic configuration?</h3>

Electronic configuration is the the arrangement of electrons in an atom, molecule, or other physical structure like a crystal.

Vanadium is the 23rd element on the periodic table and has chemical symbol V with atomic number 23. It is a transition metal, used in the production of special steels.

This suggests that the electronic configuration of Vanadium will be written as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3

Therefore, the electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3.

Learn more about electronic configuration at: brainly.com/question/14283892

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2 years ago
How many molecules of Iron(II)oxide are present in 35.2*10^-23 g of Iron (II)oxide?
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Answer:

R.F.M of Iron (II) oxide :

{ \tt{ = (56 \times 2) + (16 \times 3)}} \\  = 160 \: g

Moles :

{ \tt{ \frac{35.2 \times  {10}^{ - 23} }{160} }} \\  = 2.2 \times  {10}^{ - 24}  \: moles

Molecules :

{ \tt{ = 2.2 \times  {10}^{ - 24}  \times 6.02 \times  {10}^{23} }} \\  = 1.3244 \: molecules

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