Answer:
<h2>1565.2 kg</h2>
Explanation:
The mass of the vehicle can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>1565.2 kg</h3>
Hope this helps you
I hope this helps you...
From the center out, the layers of the Sun are as follows: the solar interior composed of the core (which occupies the innermost quarter or so of the Sun's radius), the radiative zone, and the the convective zone, then there is the visible surface known as thephotosphere, the chromosphere, and finally the outermost layer, the corona.
Atoms are the smallest particles of an element that can take part in a chemical reaction. During any chemical reaction no particles are created or destroyed: the atoms are simply rearranged from the reactants to the products. The products may have different properties to the reactants.
Mass is never lost or gained in chemical reactions. We say that mass is always conserved. In other words, the total mass of products at the end of the reaction is equal to the total mass of the reactants at the beginning.
This fact allows you to work out the mass of one substance in a reaction if the masses of the other substances are known.
Given data:
Mass of cesium chloride CsCl (m) = 52.3 g
Mass of water (mh2O)= 60.0 g
Volume of the solution (V) = 63.3 ml
Step 1: Calculate the number of moles of CsCl
Molar mass of CsCl = 168.36 g/mol
Mass of CsCl = 52.3 g
# moles = mass/molar mass = 52.3 g/168.36 g.mol-1 = 0.3106 moles
Step 2: Volume of solution in Liters
1000 ml = 1 liter
therefore, 63.3 ml corresponds to : 63.3 ml * 1 L/1000 ml = 0.0633 L
Step 3: Calculate molarity of CsCl
Molarity = moles of CsCl/volume of solution
= 0.3106 moles/0.0633 L = 4.91 moles/L
Molarity = 4.91 M
Answer: -
Hydrogen peroxide breaks down into water and oxygen.
2H₂O₂ → 2H₂O + O₂
The yeast present contains an enzyme called catalase which catalyses the reaction.
More the amount of the catalyst added, faster will be the decomposition of the hydrogen peroxide.
Thus if we added more than 5 mL of yeast solution to the 2H₂O₂, the breakdown would occur faster. Thus the bubbles and the accompanying fizz would be much more.
