It increases
The attractive force between the nucleus and the electrons INCREASES if the proton number increases while the number of energy levels remains constant.
Explanation:
Remember that protons carry a positive charge while electrons carry a negative charges. Unlike charges attract while like charges repel. An increase in the number of protons increases the positive charge of the atomic nucleus. This means that the force of attraction on the electron cloud of the atom increases.
This is why the atomic radius of atoms decreases across a period (from left to right) as the mass number of the atoms increase (while the number of electron orbitals remains the same across the period).
Learn More:
For more on the atomic radius check out;
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There are three subatomic particle that are present in an atom. These are electrons, protons, and neutrons. Among these three, I believe the <span>subatomic particle that plays the greatest part in determining the properties of and element would be the electron. It is what determines how the element would react in different conditions.</span>
The reaction mechanism for an alpha,beta-unsaturated ketone to react with basic peroxide to form an epoxide is shown below with a general ketone. The basic hydroxide is used to deprotonate the peroxide molecule to create a strong HOO- nucleophile. The peroxide then attacks the beta-carbon of the alkene and this pushes the electrons up to the oxygen of the carbonyl. This is the first intermediate that is formed during this reaction.
After the intermediate is formed, the lone pair from the oxygen pushes back down to form the carbonyl once more and this breaks a carbon-carbon bond which attacks the oxygen of the peroxy group, ultimately substituting an -OH group and forming the final epoxide ketone product.
Answer:
p orbitals only
Explanation:
Carbon has an atomic number of 6 so its electron configuration will be 1s² 2s² 2p². It has two orbitals as indicated with the 2 as its period number with the outer orbital have 4 valence electrons. So carbon is in the p-orbital, period 2 and in group 4.
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I hope this helps!
