Question

Suppose that a large pumpkin empty a swimming pool in 40 hours and that a small pumpkin empty a pool and 70 hours working together how long will it take to empty the pool

Answer 1

Answer:

Total 25.45 hours will be taken to empty the pool.

Step-by-step explanation:

Time taken by large pumpkin to empty the pool=40 hours

Time taken by the smaller pumpkins to empty the pool=70 hours

Amount of pool emptied by large pumpkin in one hour=$\frac{1}{40}$

Amount of pool emptied by small pumpkin in one hour=$\frac{1}{70}$

Amount of pool emptied in one hour if both pumpkins work together=

$\frac{1}{40}$+ $\frac{1}{70}$

=$\frac{11}{280}$

Therefore, the no. of days will be the reciprocal of the amount of work done in one hour ie . $\frac{280}{11}$

Total 25.45 hours will be taken to empty the pool.