Answer:
2-sqrt14/2, 2+sqrt13/2.
Step-by-step explanation:
What you do is you have to do the quadratic equation like it says in the problem.
x= −b± sqrtb^2 −4ac
/2a
.
a=-2, b=4, c=5.
x=-4±sqrt(4)^2-4(-2)(5)/2(-2).
x=-4±sqrt16+40/-4.
x=-4±2sqrt14/-2.
2-sqrt14/2, 2+sqrt13/2. is your answer once you have done everything.
I think the first one is a simple as it gets
for the second one it could be simplified to 6x^6-4 because u combine the x terms and distribute the power
Anything 5 and up, because when you multiply the by 15, they equal more than 65, making the inequality true.
Answer:
infinite solutions
Step-by-step explanation:
4x+4(3x+7) = 8(2x-3) +52
Distribute
4x+12x+28 = 16x-24+52
Combine like terms
16x+28 = 16x +28
Subtract 16x from each side
16x-16x+28 = 16x-16x +28
28=28
This is true, so there are infinite solutions
