Answer:
1. X is added to 8
2. Subtract 14 by a number
3. Multiply 2 after you add 3 into a number.
4.. Twice a number plus 3
5. Divide 15 by a number
Step-by-step explanation:
Answer:

Step-by-step explanation:
The opposite angles in a quadrilateral theorem states that when a quadrilateral is inscribed in a circle, the angles that are opposite each other are supplementary, their degree measures add up to 180 degrees. One can apply this here by using the sum of (<C) and (<A) to find the measure of the parameter (z). Then one can substitute in the value of (z) to find the measure of (<B). Finally, one can use the opposite angles in a quadrilateral theorem to find the measure of angle (<D) by using the sum of (<B) and (D).
Use the opposite angles in an inscribed quadrialteral theorem,
<A + <C = 180
Substitute,
14x - 7 + 8z = 180
Simplify,
22z - 7 = 180
Inverse operations,
22z = 187
z = 
Simplify,
z = 
Now substitute the value of (z) into the expression given for the measure of angle (<B)
<B = 10z
<B = 10(
)
Simplify,
<B = 85
Use the opposite angles in an inscribed quadrilateral theorem to find the measure of (<D)
<B + <D = 180
Substitute,
85 + <D = 180
Inverse operations,
<D = 95
Answer:
128 oz
Step-by-step explanation:
Add $0.50 and $0.75 till you get 10
Count the times you added them, which is 8 times (equal)
Then 8 to ounces is 128 oz
Bye, have a great Day/Night :)
-2/3x + 5 = 20 - x
subtract 5 from each side
-2/3 x = 15 -x
add x to each side
-2/3 x +x = 15
get a common denominator of 3 for the x terms
-2/3x + 3/3 x =15
combine like terms
1/3 x = 15
multiply by 3 on each side
x = 45
Answer: x=45
Answer:
36/1225 is in the simplest form.
Step-by-step explanation:
The easiest way to simplify a fraction is to look at eachs prime factorization:
36 has the factors:
(1, 2, 3, 4, 9, 12, 18 , 36)
1225 has these factors:
(1, 5, 7, 25, 35, 49, 175, 245, 1225)
Now we look for a common factor greater than 1:
Hmm... there isn't one in these sequences! With that information in our belt, we now know that 36/1225 is in its simplest form.