Answer:
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.
Answer:0.369 m
Step-by-step explanation:
Given
Distance between slit and screen is 
Wavelength 
Angle between zeroth order bright fringe and Fourth-order bright fringe is 
let distance between the slits be d
Distance of n th bright fringe From central Fringe is given by

Also 



Answer:
D) -20/-5 because a negative divided by a negative is a positive.
Step-by-step explanation:
The equation is $130 + $31.67x = 500
Subtract 130 from both sides $31.67x = $370
Divide $31.67 from both sides
X=11.68
BUT
you can’t have .68 of a day so the answer is 11 days.
Answer:
it's 100
Step-by-step explanation:
9/10 of 1000 is 900, 8/9 of 900 is 800, 7/8 of 800 is 700, 6/7 of 700 is 600, 5/6 of 600 is 500, 4/5 of 500 is 400, 3/4 of 400 is 300, 2/3 of 300 is 200, and 1/2 of 200 is 100 which makes 100 the value of 1/2 of 2/3 of 3/4 of 4/5 of 5/6 of 6/7 of 7/8 of 8/9 of 9/10 of 1000? I hope this makes sense.