I need help, I did 1-2b, but i do not mind someone answering it either way so I can double check, but I am mainly stuck with 2c
and if someone can tell me the answer and as to why, it would mean a lot and you can get brainlest if it is the right answer :) 
1 answer:
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the equation in the slope-intercept of the side of triangle ABC that is perpendicular to segment EF is y = x + 1
<h3>How to determine the equation</h3>
From the figure given, we can deduce the coordinates of the sides
For A
A ( 4,2)
For B
B ( 4, 5)
C ( 1, 2)
D ( 2, -4 )
E ( 5, -4)
F ( 2, -1)
The slope for BC
Slope =
Substitute the values for both B and C coordinates, we have
Slope =
Find the difference for both the numerator and denominator
Slope =
Slope = 1
We have the rotation for both point ( 0, 1)
y - y1 = m ( x - x1)
The values for y1 and x1 are 1 and 0 respectively and the slope m is 1
Substitute the values
y - 1 = 1 ( x - 0)
y - 1 = x
Make 'y' the subject of formula
y = x + 1
Thus, the equation in the slope-intercept of the side of triangle ABC that is perpendicular to segment EF is y = x + 1
Learn more about linear graphs here:
#SPJ1
Simon is 13 years old
Let x be Simon's age
Thus 4 years ago his age was (x - 4) and 2 years from now his age is (x + 2)
Hence 5(x - 4) = 3(x + 2)
distributing both sides gives
5x-20 = 3x + 6
subtract 3x from both sides of the equation
5x - 3x - 20 = 6
2x - 20 = 6
add 20 to both sides
2x = 6 + 20 = 26
divide both sides by 2
x = = 13
Simon is 13 years old
Notice that every pair of point (x, y) in the original picture, has become (-y, -x) in the transformed figure.
Let ABC be first transformed onto A"B"C" by a 90° clockwise rotation.
Notice that B(4, 1) is mapped onto B''(1, -4). So the rule mapping ABC to A"B"C" is (x, y)→(y, -x)
so we are very close to (-y, -x).
The transformation that maps (y, -x) to (-y, -x) is a reflection with respect to the y-axis. Notice that the 2. coordinate is same, but the first coordinates are opposite.
ANSWER:
"<span>a 90 clockwise rotation about the origin and a reflection over the y-axis</span>"
Let ABC be first transformed onto A"B"C" by a 90° clockwise rotation.
Notice that B(4, 1) is mapped onto B''(1, -4). So the rule mapping ABC to A"B"C" is (x, y)→(y, -x)
so we are very close to (-y, -x).
The transformation that maps (y, -x) to (-y, -x) is a reflection with respect to the y-axis. Notice that the 2. coordinate is same, but the first coordinates are opposite.
ANSWER:
"<span>a 90 clockwise rotation about the origin and a reflection over the y-axis</span>"