Answer:
<em>The numbers are 4 and 6</em>
<em />
Step-by-step explanation:
Let
x------> be the first positive even integer
x+2---> be the second positive even integer
<em>we know that the solution is a positive value</em>
<em />
<u>The numbers are 4 and 6</u>
Hope this helps!
<em>stay safe</em>
Answer:h = 2((A)/(b1+b2))
Step-by-step explanation:
A is the answer of not I’m sorry for that
Answer:
Below in bold
Step-by-step explanation:
The sequence is:
3, x, y, 18
If this is an A P then
x - 3 = y - x
2x - y = 3 (A) and
y - x = 18 - y
2y - x = 18 (B)
Multiply (A) by 2:
4x - 2y = 6 (C)
Adding B and C:
3x = 24
x = 8.
and
2y - 8 = 18
2y = 26
y = 13.
So x = 8 and y = 13.
b) ar + ar^2 = 6ar^3 where a = first term and r = common ratio
Divide by a:
r + r^2 = 6r^3
6r^3 - r^2 - r = 0
r(6r^2 - r - 1) = 0
r(3r + 1)(2r - 1) = 0
So the 2 possible values of r
= -1/3 and 1/2.
i) The common ratio is positive so it must be 1/2.
Second term ar = 8
1/2 a = 8
a = 16.
So the first 6 terms are:
16, 8, 4, 2, 1, 1/2.
