Question

Express 64 = 4x as a logarithmic equation

Answer 1

Note: I'm assuming you mean that $64=4^x$.

Taking the logarithm gives:

$\log{4^x} = \log{64}$

Using our rules of logarithms ($\log{a^b} = b \log a$), we have:

$x \log 4 = \log 64$

This corresponds to answer A.

Answer 2

Answer:

Option B is correct

$\log_4 64 = x$

Step-by-step explanation:

using logarithmic rules:

$\log a^b = b\log a$

$\log_n m = \frac{\log m}{\log n}$

Given the equation:

$64 = 4^x$

Take log both sides we have;

$\log 64 = \log 4^x$

Apply the logarithmic rules:

$\log 64 = x\log 4$

Divide both sides by log 4 we have;

$\frac{\log 64}{\log 4}= x$

Again, apply the logarithmic rules:

$\log_4 64 = x$

therefore, we get the given expression as a logarithmic equation is, $\log_4 64 = x$