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kondaur [170]
4 years ago
11

The regular price of a child's entry ticket to a water park is $9 less than that for an adult's. The park offers half off all en

try tickets during the off-peak season. The Sandlers paid a total of $132 for 1 adult ticket and 4 child's tickets to the water park during the off-peak season. The following equation represents this situation, where x represents the regular price of an adult ticket:
132 = one-halfx + 2(x − 9)

What is the regular price of a child's ticket?

$60
$57
$51
$42
Mathematics
1 answer:
ser-zykov [4K]4 years ago
6 0

The regular price of a child's ticket is $51

<u><em>Explanation</em></u>

If  x  represents the regular price of an adult ticket, then the regular price of a child's ticket =(x-9)

Given equations is:  132=\frac{1}{2}x+2(x-9)

<u>Solving the above equation</u>, we will get...

132=\frac{1}{2}x+2(x-9)\\ \\ 132=\frac{1}{2}x+2x-18 \\ \\ 132=\frac{5}{2}x-18\\ \\ 132+18=\frac{5}{2}x\\ \\ 150= \frac{5}{2}x\\ \\ 300=5x\\ \\ x= \frac{300}{5}=60

So, the regular price of a child's ticket =x-9=60-9= 51 dollar.

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-58 - 7x = -10x + 29

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4 years ago
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y+2 =3(x+1)

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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f(x) = \frac{x^2 - 2x}{x^2 - 4}

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f(x) = \frac{x^2 - 2x}{x^2 - 4}

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f(x) = \frac{x}{x + 2}

f(2.1) = \frac{2.1}{2.1 + 2}

f(2.1) = \frac{2.1}{4.1}

f(2.1) = 0.512195

When x = 2.05

f(x) = \frac{x}{x + 2}

f(2.05) = \frac{2.05}{2 + 2.05}

f(2.05) = \frac{2.05}{4.05}

f(2.05) = 0.506173

When x = 2.01

f(x) = \frac{x}{x + 2}

f(2.01)=\frac{2.01}{2.01 +2}

f(2.01)=\frac{2.01}{4.01}

f(2.01)=0.501247

When x = 2.001

f(x) = \frac{x}{x + 2}

f(2.001) = \frac{2.001}{2.001 +2}

f(2.001) = \frac{2.001}{4.001}

f(2.001) = 0.500125

When x = 2.0001

f(x) = \frac{x}{x + 2}

f(2.0001) = \frac{2.0001}{2.0001 + 2}

f(2.0001) = \frac{2.0001}{4.0001}

f(2.0001) = 0.500012

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f(x) = \frac{x}{x + 2}

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f(1.9) = \frac{1.9}{3.9}

f(1.9) = 0.487179

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f(x) = \frac{x}{x + 2}

f(1.95) = \frac{1.95}{1.95 + 2}

f(1.95) = \frac{1.95}{3.95}

f(1.95) = 0.493671

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f(x) = \frac{x}{x + 2}

f(1.99) = \frac{1.99}{1.99 + 2}

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f(1.99) = 0.498747

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f(1.9999) = \frac{1.9999}{3.9999}

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