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Burka [1]
3 years ago
10

Which of the equations below represents à line perpendicular to the y-axis?

Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

Its x=6

Step-by-step explanation:

I graphed it on mathaway

You might be interested in
Describe the error in the work shown.
mihalych1998 [28]

The error was in second step.

3√(y^3)^4 = y^4

(Cube root cancels cube and not power 4)

The answer should be:

xy^4/4

//Hope it helps.

4 0
3 years ago
Michelle is giving away prizes at one of her meetings.the prizes include 5 stress balls , 3 notepads , 2gift cards and 6 sticky
harina [27]

Answer:

13 out of 16 (13/16)

Step-by-step explanation:

Add all of the items together.

5 stress balls + 3 notepads + 2 gift cards + 6 sticky notes = 16 items

So, now you have to find the probability out of 16.

Since there are 5 stress balls and 2 gift cards, there is a 5 out of 16 chance of passing out stress balls(5/16) and a 2 out 16 chance of handing out gift cards(2/16)

So, she has a 3 out 16 chance of handing out stress balls more than gift cards.

hope this helps and makes sense:)

6 0
3 years ago
Solve the following: - 3 raised to 1 by 5 the whole raised to 4 (3^1/5)^4
Diano4ka-milaya [45]

Answer:

8.30256

Step-by-step explanation:

Step 1: Write out expression

((-3)^{\frac{1}{5} })^{4(3^{\frac{1}{5} })^4

Step 2: Use BPEMDAS to evaluate

(-1.24573)^{4(3^{\frac{1}{5} })^4

(-1.24573)^{4(1.24573)^4

(-1.24573)^{4(2.40822)

(-1.24573)^{9.6329}

= 8.30256

And we have our answer!

8 0
3 years ago
Find the area of the trapezoid to the nearest tenth.
erica [24]

Answer:

2.2 metres squared

Step-by-step explanation:

We need to find the area of this trapezoid.

The area of a trapezoid is denoted by:

A=\frac{(b_1+b_2)h}{2}, where b_1 and b_2 are the parallel bases and h is the height

Here, we already know the lengths of the two bases; they are 0.9 metres and 2.3 metres. However, we need to find the length of the height.

Notice that one of the angles is marked 45 degrees. Let's draw a perpendicular line from top endpoint of the segment labelled 0.9 to the side labelled 2.3. We now have a 45-45-90 triangle with hypotenuse 2.0 metres. As one of such a triangle's properties, we can divide 2.0 by √2 to get the length of both legs:

2.0 ÷ √2 = √2 ≈ 1.414 ≈ 1.4

Thus, the height is h = 1.4 metres. Now plug all these values we know into the equation to find the area:

A=\frac{(b_1+b_2)h}{2}

A=\frac{(0.9+2.3)*1.4}{2}=2.2

The answer is thus 2.2 metres squared.

<em>~ an aesthetics lover</em>

8 0
3 years ago
Write the following inequality in slope-intercept form. 6x+2y≤-46
Furkat [3]

Answer:


Step-by-step explanation:

y=mx+b

y less than or equal to -3x-23


7 0
2 years ago
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