Find the GCD (or HCF) of numerator and denominator
GCD of 18 and 20 is 2
Divide both the numerator and denominator by the GCD
18 ÷ 2
-----------
20 ÷ 2
Reduced fraction:
9
----
10
9/20
explanation:
7/10 - 1/4
14/20 - 5/20
14-5/20
9/20
Answer:
C
Step-by-step explanation:
A
(m² - 3m + 2) / (m² - m)
we see due to a little bit of experience with expressions and multiplications of expressions that
(m² - 3m + 2) = (m - 2)(m - 1)
(m² - m) = m(m - 1)
so,
(m - 2)(m - 1) / (m(m - 1)) = (m - 2) / m
so, that's not it.
B
(m² - 2m + 1) / (m - 1)
we see again
(m² - 2m + 1) = (m - 1)(m - 1)
so,
(m - 1)(m - 1) / (m - 1) = m - 1
so, that's not it.
C
(m² - m - 2) / (m² - 1)
we see again
(m² - m - 2) = (m - 2)(m + 1)
and
(m² - 1) = (m + 1)(m - 1)
so,
(m - 2)(m + 1) / ((m + 1)(m - 1)) = (m - 2) / (m - 1)
yes, that is the solution.
D
(2m² - 4m) / (2(m - 2))
2m(m - 2) / (2(m - 2)) = 2m/2 = m
no, that is not a solution.
Put it on the graph as 2xy=10!
Answer:
Step-by-step explanation:
Z -2.02
x 10
µ 22.5
σ 6.2
