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amm1812
2 years ago
10

2. Find the value of x to the nearest degree. A) 68 B) 22 C) 24 D) 66

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
6 0

Answer:

it would be 66 I hope this helps.

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20 yards 8 inches is divided into 26 equal sections, how long is each section
hoa [83]
In the given question, there are several information's of immense importance and worth taking a look. based on these information's, the answer to the question can be easily determined.The length that has to be divided into 26 equal parts is 20 yards and 8 inches.Firstly we have to change the yard into inches and then we can divide the total inches into 26 equal parts.
We know
1 yard = 36 inches
20 yards = 720 inches
Then the total length that has to be divided = (720 + 8) inches
                                                                     = 728 inches
Now we have to divide the 728 inches into 26 equal parts.
Length of each section = (728/26) inches
                                      = 28 inches.
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5 0
3 years ago
How do you show a model for 3/4× 1/3
Mila [183]
You multiply the numerator and denominator of 3/4 with 3 and multiply 1/3 with 4 on the bottom and top and after  you get 36/144 you simplify it and you get 1/4 so thats your answer
 
4 0
3 years ago
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Which of the following is an example of the atmosphere inracting with the biosphere
Paha777 [63]

Answer:

rain (hydrosphere) falls from clouds in the atmosphere to the lithosphere and forms streams and rivers that provide drinking water for wildlife and humans as well as water for plant growth (biosphere)

Step-by-step explanation:

7 0
2 years ago
Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl
lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13

x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88

x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63

x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38

x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13

So, the table becomes:

\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}

Next, calculate the mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}

\bar x = \frac{1845.73}{146}

\bar x = 12.64

Next, the sample variance is:

\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}

So, we have:

\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}

\sigma^2 = \frac{2393.6875}{145}

\sigma^2 = 16.51

The sample standard deviation is:

\sigma = \sqrt{\sigma^2}

\sigma = \sqrt{16.51}

\sigma = 4.06

6 0
2 years ago
Round 76.3 to the nearest whole number
cestrela7 [59]
76.3 rounded to the nearest whole number is 76
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3 years ago
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