Answer:
Option D
When the Moon is at right angles to the direction of the Sun.
Explanation:
The moon does not shine on its own, for example, like the sun that emits light as a consequence of its temperature. Instead, the moon is reflecting the sunlight (that is known as albedo).
The moon orbits the earth in a time 27.3 day, a sidereal period. According to that and the fact the Earth orbits the Sun, the moon will show different phases when is reflecting the sunlight along a month due to the configuration of those three celestial objects (Moon, Earth and the Sun).
When there is a Right angle between the Moon and to the direction of the Sun, half its face will appear to be illuminated in the night sky (that is called First Quarter).
Notice that when the Moon is between the Earth and the Sun it will be illuminated in its back, so it is not possible to see it from the Earth (that is called new moon).
However, a solar eclipse doesn't happens every month since the orbital plane of the moon is not in the same plane as the Earth's orbital plane with respect to the Sun.
Answer:
mass- the amount of matter in an object
balance- tool used to measure mass
scale- a tool used to measure weight
weight- the downward pull on an object due to gravity
<span>Humberto builds two circuits using identical components,
and then adds components to each circuit.
Circuit 1:
A series circuit with three lightbulbs.
Then add three more lightbulbs in series.
Circuit 2:
A parallel circuit with three lightbulbs
Then add two more lightbulbs on new branches
in parallel with each original bulb.
After adding the new lightbulbs in Circuit 1:
-- the voltage across each of the original bulbs is less,
-- the current through the whole series circuit is less,
-- the original three bulbs shine dimmer than before, and
-- the total power delivered from the battery is less.
-- The battery lasts longer.
After adding the new lightbulbs in Circuit 2:
</span>-- the voltage across each of the original bulbs is doesn't change,
-- the current through each original bulb doesn't change,
-- the original three bulbs shine just as bright as before,
-- the total currrent drawn by the circuit, and the total current
delivered by the battery, increases, and
-- the total power delivered from the battery increases.
-- The battery runs down sooner.
Answer:5.45X10^3m
Explanation:So use the formula,v= fλ
3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer
