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Keith_Richards [23]
3 years ago
15

Two adjacent natural frequencies of an organ pipe are found to be 550. Hz and 650. Hz. (a) Calculate the fundamental fre- quency

of the pipe. (b) Is the pipe open at both ends or open at only one end? (c) What is the length of the pipe?
Physics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

a) 100Hz

b) opened at both ends

c) 1.72m

Explanation:

Let fun be the nth Harmonic frequency organ. If pipe is opened at both ends.

L= length of pipe

Fyn =(n/x)

550hz= (n/2L)v 1

650hz=(n+1/2L)×v 2

Comparing 1 and 2

650hz= nv/2L + v/2L

550= 343/2L

L= 550×2/343 = 1.7m

c) fundamental frequency

Fo= nv/2L = 343/(2×1.7) = 100Hz

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3 years ago
A package of mass 5 kg sits on an airless asteroid of mass 7.6 × 1020 kg and radius 8.0 × 105 m. We want to launch the package i
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Answer:

s =  1.7 m

Explanation:

from the question we are given the following:

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mass of the asteriod (M) = 7.6 x 10^{20} kg

radius = 8 x 10^5 m

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spring constant (k) = 2.8 N/m

compression (s) = ?

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