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Keith_Richards [23]

3 years ago

15

Two adjacent natural frequencies of an organ pipe are found to be 550. Hz and 650. Hz. (a) Calculate the fundamental fre- quency

of the pipe. (b) Is the pipe open at both ends or open at only one end? (c) What is the length of the pipe?

1 answer:

liubo4ka [24]3 years ago

8 0

Answer:

a) 100Hz

b) opened at both ends

c) 1.72m

Explanation:

Let fun be the nth Harmonic frequency organ. If pipe is opened at both ends.

L= length of pipe

Fyn =(n/x)

550hz= (n/2L)v 1

650hz=(n+1/2L)×v 2

Comparing 1 and 2

650hz= nv/2L + v/2L

550= 343/2L

L= 550×2/343 = 1.7m

c) fundamental frequency

Fo= nv/2L = 343/(2×1.7) = 100Hz

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Read 2 more answers

An oil film with refractive index 1.48 and thickness 290 nm is floating on water and illuminated with white light at normal inci

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