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almond37 [142]
3 years ago
5

The gas phase decomposition of nitrogen dioxide at 383 °C

Chemistry
1 answer:
Anna71 [15]3 years ago
3 0

Answer:

[NO_2]=0.112M

Explanation:

Hello there!

In this case, since the second-order integrated law is given by the following equation:

\frac{1}{[NO_2]} =\frac{1}{[NO_2]_0}+kt

Thus, given the initial concentration of the nitrogen dioxide gas, the rate constant and the elapsed time, we obtain:

\frac{1}{[NO_2]}= \frac{1}{0.477M} +0.54M^{-1}s^{-1}\\\\\frac{1}{[NO_2]}=8.933M^{-1}

[NO_2]=\frac{1}{8.933M^{-1}} =0.112M

Best regards!

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Which of the following has the greatest mass? (1pt)
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C) 5 moles of Argon (Ar)

Explanation:

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7 0
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How much energy is required to heat 87.1 g acetone (molar mass=58.08 g/mol) from a solid at -154.0°C to a liquid at -42.0°C? The
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Answer:

The answer to the question above is

The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C = 29.36 kJ

Explanation:

The given variables are

ΔHfus = 7.27 kJ/mol

Cliq = 2.16 J/g°C

Cgas = 1.29 J/g°C

Csol = 1.65 J/g°C

Tmelting = -95.0°C.

Initial temperature = -154.0°C

Final temperature = -42.0°C?

Mass of acetone = 87.1 g

Molar mass of acetone = 58.08 g/mol

Solution

Heat required to raise the temperature of solid acetone from -154 °C to -95 °C or 59 °C is given by

H = mCsolT = 87.1 g* 1.65 J/g°C* 59 °C = 8479.185 J

Heat required to melt the acetone at -95 °C = ΔHfus*number of moles =

But number of moles = mass÷(molar mass) = 87.1÷58.08 = 1.5

Heat required to melt the acetone at -95 °C =1.5 moles*7.27 kJ/mol = 10.905 kJ

The heat required to raise the temperature to -42 degrees is

H = m*Cliq*T = 87.1 g* 2.16 J/g°C * 53 °C = 9971.21 J

Total heat = 9971.21 J + 10.905 kJ + 8479.185 J = 29355.393 J = 29.36 kJ

The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C is 29.36 kJ

4 0
4 years ago
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hope this helps!

6 0
3 years ago
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