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xeze [42]
3 years ago
8

Do you hace a copy of the student guide for this lab, including your date table?

Chemistry
2 answers:
kondor19780726 [428]3 years ago
7 0

Answer:

yes i do

Explanation:

Veronika [31]3 years ago
3 0

Answer:

just click yes lol

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A flexible container is put in a deep freeze. Its original volume is 3.00 m3 at 25.0°C. After the container cools, it has shrunk
Rzqust [24]
This is an ideal gas problem. The gas inside the balloon is considered ideal. Ideal gas equation is a function pressure, temperature, amount and volume. Note: amount is constant since the balloon ins closed. Pressure is maintained constant since the walls are flexible. Ideal gas equation is: PV=nRT. Put all constant in one side and variables in one. 

P/nR=T/V. To find the answer to the question equate the constants of both situation 
T1/V1=T2/V2
(25+273.15)/3=(x+273.15)/2
x=-74.38 degC 
4 0
3 years ago
GIVING BRAINLIEST FIVE STARS AND HEART!
iren [92.7K]

Explanation:

When an object is at rest, the body is said to possess potential energy. In another case, when the object is in motion, then it is said to possess kinetic energy. Potential energy tends to affect the object within the environment if and only when it gets transformed to other kinds of energy.

4 0
3 years ago
How many liters of NH 3 are needed to react completely with 30.0 L of NO (at STP)?
aleksklad [387]

Answer:

20.8 Lof NH₃ are needed for the reaction

Explanation:

This is the reaction:

4 NH₃  +  6 NO  →  5N₂  +   6H₂O

and the info. we need

Ammonia density = 0,00073 g/mL

Let's determine the moles of NO at STP by the Ideal Gases Law equation

P . V = n . R .T

1atm . 30L = n . 0.082 . 273K

(1atm . 30L) / (0.082 . 273K) = n → 1.34 moles of NO

Let's find out the amount of ammonia that should react

6 mol of NO react with 4 mol of ammonia

1.34 mol of NO will react with (1.34  .4)/6 = 0.893 moles of ammonia

Molar mass NH₃ = 17 g/m

0.893 mol . 17 g/m = 15.19 g of ammonia

Ammonia density = 0,00073 g/mL = NH₃ mass / NH₃ volume

0,00073 g/mL = 15.19 g / NH₃ volume

NH₃ volume = 15.19 g / 0,00073 g/mL → 20805.5 mL ⇒ 20.8 L

6 0
3 years ago
When hydrogen is attached to a more electronegative element?
sesenic [268]
When hydrogen is attached to a more electronegative element, the more electronegative atom becomes partially negative.
5 0
3 years ago
Read 2 more answers
What is the volume of 6.9 mol oxygen (O2) gas at 233 K and a pressure of 4.0 atm? (The universal gas constant is 0.0821 L•atm/mo
Art [367]

Volume of Oxygen O2 would be 33 L.

Solution : Given information - Mole (n) = 6.9 mol

Pressure (P) = 4.0 atm

Temperature (T) = 233 K

Universal gas constant (R) = 0.0821 L.atm/mol.K

Volume(V) is unknown , which we need to find.

Volume can be calculated by using the Ideal gas equation which is :

PV = nRT  (Ideal gas equation)

On rearranging the above formula we will get :

V = \frac{nRT}{P}

Where , P = pressure , V = volume , n = mole , R = universal gas constant , T = temperature.

We will plugin the values of P , n , R and T in the ideal gas equation and then calculate Volume (V)

V = \frac{nRT}{P}

V = \frac{(6.9mol\times 0.0821\frac{L.atm}{mol.K}\times 233K)}{4.0atm}

V = \frac{131.99217 L}{4.0}

V = 32.998 L or 33 L


8 0
3 years ago
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