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3 years ago

Find the slope Help pls due in one hour

Mathematics

1 answer:

user100 [1]3 years ago

3 0

Answer:

-5/4 for your rise/run which is the slope

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-2x-2+x^2+x+180+-2x-2=180

Dominik [7]

Answer:

x= 4, -1

Step-by-step explanation:

-2x - 2 + x^2 + x + 180 - 2x - 2 = 180

add like terms and put in descending order

x^2 - 3x + 176 = 180

subtract 180 from both sides

x^2 - 3x - 4 = 0

factor out the equation

(x-4)(x+1)=0

solve for x

x-4=0 x+1=0

x=4 x=-1

5 0

2 years ago

£620 is divided between Malachy, Paul & Brian so that Malachy gets twice as much as Paul, and Paul gets three times as much

geniusboy [140]

Answer: Paul gets £186

Step-by-step explanation:

Paul has 1/2 as much as Malachy, and Brian has 1/3 as much Paul, therefore Brian has 1/6 as much as Malachy.

1/2 * 1/3 = 1/6

So Malachy’s amount equals 1 in this equation, Paul’s amount equals 1/2 in this equation, and Brian’s amount equals 1/6 in this equation.

1 + 1/2 + 1/6 = 1 + 3/6 + 1/6 = 1 4/6

Now, divide 620 by 1 4/6 to find Malachy’s amount.

620/1 4/6 = 372

Now, divde 372 by 2 to get Paul’s amount.

372/2 = 186

3 0

2 years ago

Synthetic Division x^3+9x^2-11x-13

olga nikolaevna [1]

Answer:

You can't synthetic divide since there's no dividend. As you can't factor it so I figure you must've forgot to include something or there's no solution.

8 0

2 years ago

What is the range of f(x)=-3^x+4

Mice21 [21]

The range is [4,∞)
Or from 4 to positive infinity
Or y is greater than or equal to 4

5 0

2 years ago

Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.

Mama L [17]

Multiplying both sides by $y^2$ gives

$xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1$

so that substituting $v=y^3$ and hence $\frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx}$ gives the linear ODE,

$\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1$

Now multiply both sides by $3x^2$ to get

$x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2$

so that the left side condenses into the derivative of a product.

$\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2$

Integrate both sides, then solve for $v$ , then for $y$ :

$x^3v=\displaystyle\int3x^2\,\mathrm dx$

$x^3v=x^3+C$

$v=1+\dfrac C{x^3}$

$y^3=1+\dfrac C{x^3}$

$\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}$

6 0

3 years ago