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Liono4ka [1.6K]
3 years ago
5

What is the value of the expression 5x2-8x+4 when x = -3

Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0

Answer:

5 x 2 - 8x + 4

5 x 2 - 24 + 4

10 - 24 + 4

-10

Answer: -10

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Factor the expression by finding the GCF. 16m2 − 12m
ziro4ka [17]

Answer:

4m(4m-3)

Step-by-step explanation:

16m^2 − 12m

16 m^2 = 2*2*2*2*m*m

12m = 2*2*3*m

The greatest factor for 16m^2 and 12m is 2*2*m  or 4m

Factor out 4m

16 m^2 = 2*2*2*2*m*m = 4m(2*2m)=4m(4m)

12m = 2*2*3*m = 4m(3)

Factoring out 4m

16m^2 − 12m

4m(4m-3)

3 0
3 years ago
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True or false;<br> If two planes cross one another, then their intersection is two lines.
Vlad1618 [11]
If they intersect eachother then the answer is true
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3 years ago
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Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x&gt;1
Lera25 [3.4K]
Assuming the function is

f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}

For f(x) to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)
\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)
\iff2=b+c

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

f'(x)=\begin{cases}2&\text{for }x1\end{cases}

\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)
\iff2=2b+c

Now we solve for b and c:

\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2
5 0
3 years ago
HELP ASAP!!!! <br> EXTRA POINTS!!
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20%. total= 5 => total= 25

8 0
3 years ago
HELLLLLLLLLPPPPPPP The difference of two numbers is 8 and their quotient is 2
Dmitriy789 [7]

Answer:

x-y =8

x/y=3

=> 3y-y=8

=> 2y = 8

=> y = 4

=> x = 4+8 =12

3 0
3 years ago
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