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andrew11 [14]
2 years ago
8

Multiple choice please help!!

Mathematics
1 answer:
AveGali [126]2 years ago
5 0

3 and 4

Step-by-step explanation:

y=5x

y=5(0)

y=0

y=5x

y=5(10)

y=50

y=5x

y=5(51)

y=255

y=5x

y=5(400)

y=2000

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Combine the like terms to make a simpler expression: <br> −3k−(−8)+2
Alex777 [14]
The answer to this question is: -3k+10
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Simplify the expression. Write your answer as a power.<br> (-6)* • (-6)*
jeyben [28]

Answer:

-6^2 or -6 to the second power :)

Step-by-step explanation:

if i got it correct can i get brainliest answer

5 0
3 years ago
I need help solving this
Stolb23 [73]

Step-by-step explanation:

So in the equation given, y = 2x - 3

you substitute x for whats given in the table in the x column.

Example

In the graph the first number under the x colum is -1.

y = 2x - 3 in the equation you take out x and put -1.

So now the equation becomes y = 2 × -1 - 3.

Using bedmas to solve the question you should get -5

Which now means y = -5

To plot the point now x would be -1 and y would be -5 (-1, -5)

Same thing for the second number in the x Column.

y = 2 × 1 - 3 which equals -1

To plot it

x = 1 y = -1. (1, -1)

And for the last number 3.

Agai. You substitute x for 3 which makes the equation y = 2 × 3 - 3

this gives you 3 and to plot it

x would be 3 and y would be 3

4 0
3 years ago
Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=
luda_lava [24]

Let f(x) = x^3 - 2x - 2. Then differentiating, we get

f'(x) = 3x^2 - 2

We approximate f(x) at x_1=2 with the tangent line,

f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18

The x-intercept for this approximation will be our next approximation for the root,

10x - 18 = 0 \implies x_2 = \dfrac95

Repeat this process. Approximate f(x) at x_2 = \frac95.

f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}

Then

\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}

Once more. Approximate f(x) at x_3.

f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}

Then

\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}

Compare this to the actual root of f(x), which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0
2 years ago
Alex bought string for $125. Other materials for $18. What is the total cost to make 50 puppets?
Lesechka [4]
(125+18) 50 = $7,150
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3 years ago
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