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Amanda [17]
3 years ago
11

Ardi and Lei are both travelling by train. Ardi's train travels 70 km in 35 minutes. Lei's train travels 585 km. It leaves at 9:

05 and arrives at 13:35. Work out the difference, in km/h, between the average speed of their trains.
Mathematics
1 answer:
Leni [432]3 years ago
3 0

Answer:

10 km/hr

Step-by-step explanation:

Average speed = Total distance travelled / Total time taken

Ardi:

Total distance travelled = 70 km

Total time taken = 35 minutes = 35/60 hour

Average speed = Total distance travelled / Total time taken

= 70 km ÷ 35/60 hr

= 70 × 60/35

= 4,200/35

= 120 km/hr

Lei:

Total distance travelled = 585 km Total time taken = 9:05 - 13:35 = 4 hours 30 minutes

= 4.5 hours

Average speed = Total distance travelled / Total time taken

= 585 km / 4.5 hours

= 130 km/hr

Difference, in km/h, between the average speed of their trains = Lei's train - Ardi's train

= 130 km/hr - 120 km/hr

= 10 km/hr

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Answer:

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Step-by-step explanation:

{x}^{2}  + 6x - 7 = (x  + 3)  {}^{2}  - (3) {}^{2}  - 7 \\  = (x + 3) {}^{2}  - 16

3 0
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Martin has 64 sticks of gum altogether. How many packs of gum does he have?
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Algebra 1 : ordered pairs kinda dont get it
lesantik [10]

Answer:

<em>Option C; 3x - y = -27 and x + 2y = 16</em>

Step-by-step explanation:

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<em />

6 0
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6. An ostrich cannot fly, but it is able to run fast. Suppose an ostrich runs east for 7.95 s and then runs 161 m south, so that
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Answer:

159 m

Step-by-step explanation:

From the information given:

It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.

Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.

Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.

We are to find, the magnitude of the ostrich's eastward component.

i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.

Using the Pythagoras rule:

ES² = OE² + OS²

226² = OE² + 161²

226² -  161² = OE²

OE²  =  226² -  161²

OE²  = 51076 - 25921

OE²  =  51076 - 25921

OE²  =  25155

OE = \sqrt{25155}

OE =  158.60 m

OE ≅ 159 m

Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.

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