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Verizon [17]
2 years ago
13

A point on a pre-image is currently located at (1, -3). The pre-image is translated 3 units right and 6 units up. What are the N

EW coordinates for the point after the translation? Use graph paper to sketch the translation if needed. Question 3 options:
A. (3, 4)
B. (4, 3)
C. (7, 0)
D. (-2, 2)
Mathematics
2 answers:
Alex_Xolod [135]2 years ago
5 0

Answer:

are you from k-12? bc if so im also stuck on this question

Step-by-step explanation:

erastovalidia [21]2 years ago
4 0

Answer:(4,3)

Step-by-step explanation: 6+-3=3 and 1 to the right 3 times is 4

You might be interested in
8/3 X 7/10 X 6/1 plz help me
Harlamova29_29 [7]

Answer:

are you mutiplying?

Step-by-step explanation:

5 0
3 years ago
Rewrite in simplest radical form: x^4/5 / x^1/3 into a√x^b
mrs_skeptik [129]

Answer:

\sqrt[15]{x^7}

Step-by-step explanation:

If we have the expression

\frac{x^{\frac{4}{5}}}{x^{\frac{1}{3}}}, we have to think about exponent rules.

If we have a^b \div a^c, then the value will be equal to a^{b-c}.

So \frac{x^{\frac{4}{5}}}{x^{\frac{1}{3}}} simplified will be x^{\frac{4}{5} - \frac{1}{3}}

Converting \frac{4}{5} and \frac{1}{3} into fifteenths (lcm) gets us \frac{12}{15} - \frac{5}{15} = \frac{7}{15}.

We can convert x^{\frac{7}{15}} into a radical by taking the denominator root of x to the numerator.

\sqrt[15]{x^7}.

Hope this helped!

6 0
3 years ago
State the domain and range of the relation. Determine whether the relation represents a function.
dangina [55]

Answer:

Domain {-2,0,2}

Range {-2,0,2}

Relation is a Function

Step-by-step explanation:

We are given a relation:

{ (-2,-2) , (0,0) , (2,2) }

Domain can be defined as the all possible values of x for a relation. It is considered as a set of all first values of the ordered pairs of a given relation.

Domain of the given relation is {-2,0,2}

Range can be defined as all possible value of y which corresponds to the values of x in the domain. It is considered as a set of all second values of the ordered pairs of a given relation.

Range of the given relation is {-2,0,2}

A relation is a function if only there is one value of y for each value of x. If in the set of ordered pair of the relation, the value of x gets repeated, then the relation is not a function.

As no values of x are getting repeated, the relation is a function.

4 0
3 years ago
9. a. Maurice says that 1079 ÷ 62 is 16 with a remainder of 87. a. Without seeing his work, how can you tell Maurice divided inc
mamaluj [8]

Answer:

a.  We can tell that Maurice divided incorrectly because if the dividend is 62, you can't have a remainder of 87, because 62 goes into 87 once, so the answer would be 17 with a remainder of 25.  B. YOu can use that fact to find the correct quotient, because 87/62 is 1, with a remainder of 25, so 16+1=17, so the answer is 17 with a remainder of 25.   Please vote the brainliest.

Step-by-step explanation:

8 0
3 years ago
The sum of three consecutive whole numbers is 183 find the numbers
sergiy2304 [10]

Answer:

let the no.s be : x, x+1, x+2

then,

=> x + x+1 + x+2 = 183

=> 3x + 3 = 183

=> 3x     = 183 - 3

=> x  =  180/3

=> x = 60

therefore,  the whole no.s are 60, 61, and 62

8 0
3 years ago
Read 2 more answers
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