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Rom4ik [11]
3 years ago
8

What is the area of this shape?

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer: the link you posted is the area of the shape

Step-by-step explanation:

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Solve the inequality s-12 _> -1
My name is Ann [436]

Answer:

s >= 11

Step-by-step explanation:

s-12 >= -1

Add 12 to both sides

s >= 11

8 0
3 years ago
Please help me asap.<br> Prove that:<br><br> Sin(A+B).Sin(A-B)=Sin²A.Sin²B
kow [346]

Answer:  Sin²A.Sin²B*

7 0
2 years ago
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On Thursday, a website received x advertisement orders. On Friday, the website received 8 more advertisement orders than on Thur
gladu [14]

Answer:

2x+8

Step-by-step explanation:

6 0
3 years ago
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Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a
Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.064

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

6 0
3 years ago
Question Help The mean finish time for a yearly amateur auto race was 185.64 minutes with a standard deviation of 0.314 minute.
Inga [223]

Answer:

Sam has the more convincing victory with a greater Zscore value

Step-by-step explanation:

Given that :

Year 1:

Mean finish time (m) = 185.64

Standard deviation (s) = 0.314

Sam's time (x1) = 185.29

Year 2:

Mean finish time (m) = 110.3

Standard deviation (s) = 0.129

Rita's time (x1) = 110.02

Zscore = (x - mean) / standard deviation

Sam's Zscore :

(185.29 - 185.64) / 0.314

= - 0.35 / 0.314

= −1.114649

= - 1.115

Rita's Zscore :

(110.02 - 110.3) / 0.129

= - 0.28 / 0.129

= −2.170542

= - 2.171

Sam has the more convincing victory with a greater Zscore value

5 0
2 years ago
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