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lidiya [134]
2 years ago
5

What is 13 minus 4/7

Mathematics
1 answer:
otez555 [7]2 years ago
4 0
13 - 4/7 = <span>12.4285714286 Or when you round it 12.43</span>
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3*(-4) really confuses need help
Arturiano [62]

Answer:

-12

Step-by-step explanation:

When you multiply a positive by a negative, the answer is always a negative. If you multiply two negatives, the answer is always positive. If you multiply 2 positives, the answer will always be positive.

7 0
3 years ago
15% of the parking spaces at a school are reserved. The school has 12 reserved spaces. How many parking spaces are there in tota
Strike441 [17]

Answer: 76

Step-by-step explanation:

well, we know that 15% of the X is 12, so we first use 6 15%, which is 90% 6X12=72. next, we would use 12/3, which is 4. 72+4=76.

3 0
2 years ago
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Please help, needed fast
Naya [18.7K]

Answer:

46

Step-by-step explanation:

6*5

-2*-8

30+16=46

5 0
2 years ago
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What is the slope of the line that goes through (2, 5) and (-6, -2) ?
alexira [117]
Answer:
slope = 7/8

Explanation:
Slope of the line can be calculated using the following equation:
slope = \frac{y2 - y1}{x2 - x1}

The two points given are:
(2,5) representing (x1 , y1)
(-6,-2) representing (x2 , y2)

Substitute with the points in the above equation to get the slope as follows:
slope = \frac{-2 - 5}{-6 - 2} = 7/8

Hope this helps :)

7 0
3 years ago
Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon
Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

(c) ¬((p→q)→¬(q→p))

Step-by-step explanation

taking into account the truth table for the conditional connective:

<u>p | q | p→q </u>

T | T |   T    

T | F |   F    

F | T |   T    

F | F |   T    

(a) and (b) can be seen from truth tables:

for (a) <u>p∧q</u>:

<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>

T | T |  F  |   F     |    T       |  T

T | F |  T  |  T      |    F       |  F

F | T |  F  |  T      |    F       |  F

F | F |  T  |  T      |    F       |  F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

<u>p | q | ¬p | ¬p→q | p∨q</u>

T | T |  F  |   T     |    T    

T | F |  F  |   T     |    T    

F | T |  T  |   T     |    T    

F | F |  T  |   F     |    F    

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

4 0
3 years ago
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