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3 years ago

Need help ASAP!!! Tysm if you answer!! IF YOU ANSWER RIGHT AND GET BRAINLIEST!!

Mathematics

1 answer:

Delvig [45]3 years ago

8 0

Answer:

$a_n = 3 ({5})^{n - 1}$

Step-by-step explanation:

The given sequence is 3,15,75,375,...

The first term of this geometric sequence is

$a_1=3$

The common ratio is

$r = \frac{15}{3} = 5$

The explicit formula is given by:

$a_n = a_1 {r}^{n - 1}$

We plug the first term and common ratio into the formula to get:

$a_n = 3 ({5})^{n - 1}$

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mr.young has 30 times as many pencils as jack. the whole school has 200 times as many pencils as jack. if jack has 2 pencils, ho

inna [77]

Mr.young has 60 pencil and the school has 400 pencils.
I'm not quite sure, but i think this is the answer

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4 years ago

He made a queen-sized quilt that was 8 feet long. its area was 64 feet. what is its perimeter

SOVA2 [1]

Depends on the shape we are talking here. I believe you are taking about a square, so:
The equation for area for a square is: s^2, s representing the length of 1 of the squares sides (a square is even all the way around, so 1 side is the same as all)
8^2=64, so I can assume this is a square by this. Knowing it's a square, and that one of the sides is equal to 8, and the other 3 sides are the same length, I can do 8*4, which equals 24.
The perimeter is 24

4 0

4 years ago

If logb2=x and logb3=y, evaluate the following in terms of x and y:

Alja [10]

$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

Solution:

Given that,

$log_b2 = x\\\\log_b3 = y --------(i)$

Use the following log rules

Rule 1: $log_b(ac) = log_ba + log_bc$

Rule 2: $log_b\frac{a}{c} = log_ba - log_bc$

Rule 3: $log_ba^c = clog_ba$

$a) log_b{162}$

Break 162 down to primes:

$162 = 2^1 \times 3^4$

$log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y$

Thus we get,

$log_b162 = x + 4y$

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

3 0

3 years ago

8-6x>-18 solve for x

EleoNora [17]

Answer:

x=5

Step-by-step explanation:

Well all i did was guess a random number from 1-10 so I could see what numbers make the equation bigger than -18 and the fist thing I guessed was 5 so this is what I did

8-6*5=-22

And them I said let me see if any multiples equal -18 so I went to for and did this

8-6*4=-16

That's when I guessed the answer if i looked at the sign correctly!

8 0

3 years ago

ABCD is an isosceles trapezoid with legs AB and CD, and base BC. If the length of AB = 6y +5, the length of BC= 4y - 6, and the

sertanlavr [38]

ABCD is an isosceles trapezoid with legs AB and CD
∴ AB = CD

AB = 6y +5

CD= 2y +1

∴ 6y + 5 = 2y + 1
6y - 2y = 5 - 1
4y = 4

∴ y = 4/4 = 1

8 0

4 years ago