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3 years ago

Two forces act in opposite directions on an object. If no other forces act on the object, then it will accelerate

Physics

1 answer:

Viktor [21]3 years ago

5 0

Answer:

if the net force is greater than zero

Explanation:

If two forces acts in opposite directions on an object and no other forces acts on the object, it will accelerate if the net force acting on it is greater than zero.

Acceleration is brought about the net force acting on a body if it is greater than zero.

When the net force on a body is zero, a body will not accelerate and will continue to remain in its state of rest of maintain a uniform unaccelerated motion.

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For a home sound system, two small speakers are located so that one is 52 cm closer to the listener than the other. What is the

alekssr [168]

You'll get destructive interference if both waves are the same frequency but the peaks of one wave overlap the troughs of the other wave.

That can only happen if one wave has to travel (1/2 wavelength) farther than the other one to reach your ears. So we want to find the lowest frequency for which 52 cm is 1/2 of a wavelength ... the wavelength is 104 cm.

Frequency = (speed) / (wavelength)

Frequency = (344 m/s) / (104 cm)

Frequency = (344 m/s) / (1.04 meter)

Frequency = (344 / 1.04) per second

Frequency = 330.8 Hz .

7 0

3 years ago

Each statement below is a definition or an example of force, work, potential energy, or kinetic energy. Drag each into the box t

marshall27 [118]

Answer:

yes

Explanation:

6 0

3 years ago

A chunk of metal has a volume of

Alla [95]

Answer:

7213.7kg/m³

Explanation:

Given parameters:

Volume of the metal chunk = 0.131m³

Mass of the metal chunk = 945kg

Unknown:

Density of the metal chunk = ?

Solution :

To solve this problem, density is the mass per unit volume. It is mathematically expressed as;

Density = $\frac{mass}{volume}$

So;

Density = $\frac{945}{0.131}$ = 7213.7kg/m³

5 0

3 years ago

A 1,250 W electric motor is connected to a 220 Vrms, 60 Hz source. The power factor is lagging by 0.65. To correct the pf to 0.9

Black_prince [1.1K]

Answer:

$C = 46.891 \mu F$

Explanation:

Given data:

v = 220 rms

power factor = 0.65

P = 1250 W

New power factor is 0.9 lag

we knwo that

$s = \frac{P}{P.F} < COS^{-1} 0.65$

$S = \frac{1250}{0.65} < 49.45$

s = 1923.09 < 49.65^o

s = [1250 + 1461 j] vA

$P.F new = cos [tan^{-1} \frac{Q_{new}}{P}]$

solving for $Q_{new}$

$Q_{new} = P tan [cos^{-1} P.F new]$

$Q_{new} = 1250 [tan[cos^{-1}0.9]]$

$Q_{new} = 605.40 VARS$

$Q_C = Q - Q_{new}$

$Q_C = 1461 - 605.4 = 855.6 vars$

$Q_C = \frac[v_{rms}^2}{xc} =v_{rms}^2 \omega C$

$C = \frac{Q_C}{ v_{rms}^2 \omega}$

$C = \frac{855.6}{220^2 \times 2\pi \times 60}$

$C = 4..689 \times 10^{-5}$ Faraday

$C = 46.891 \mu F$

6 0

4 years ago

Three capacitors are connected as follows: 2.8 F capacitor and 5.57 F capacitor are connected in series, then that combination i

DedPeter [7]

ANSWER

8.99 F

EXPLANATION

We know that two capacitors of capacitances 2.8 F and 5.57 F are connected in series, while a third capacitor of capacitance 7.13 F is connected in parallel to that combination,

The capacitance works similarly to the resistance, except that when capacitors are connected in parallel, their capacitances add up, while when they are connected in series, the equivalent capacitance is like we were finding the equivalent resistance of resistors connected in parallel,

$C_{eq}=\frac{1}{\frac{1}{C_1}+\frac{1}{C_2}}+C_3=\frac{1}{\frac{1}{2.8F}+\frac{1}{5.57F}}+7.13F\approx8.99F$

Hence, the total capacitance is 8.99 F, rounded to the nearest hundredth.

6 0

2 years ago