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kvasek [131]
3 years ago
13

What is the magnetic field strength, in units of microTesla (T), at a distance of 6.3 cm from a long straight wire carrying a cu

rrent of 6.5 A?

Physics
1 answer:
bezimeni [28]3 years ago
7 0

Answer:

2.1 \mu T

Explanation:

The magnetic field strength is given by:

B=\frac{\mu_0 I}{2 \pi r}

where

\mu_0 is the vacuum permeability

I is the current

r is the distance from the wire

In this problem,

I = 6.5 A

r = 6.3 cm = 0.063 m

So, the magnetic field strength is

B=\frac{(1.256\cdot 10^{-7} H/m)(6.5 A)}{2 \pi (0.063 m)}=2.1\cdot 10^{-6} T=2.1 \mu T

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