Question

What is the magnetic field strength, in units of microTesla (T), at a distance of 6.3 cm from a long straight wire carrying a current of 6.5 A?

Answer 1

Answer:

$2.1 \mu T$

Explanation:

The magnetic field strength is given by:

$B=\frac{\mu_0 I}{2 \pi r}$

where

$\mu_0$ is the vacuum permeability

I is the current

r is the distance from the wire

In this problem,

I = 6.5 A

r = 6.3 cm = 0.063 m

So, the magnetic field strength is

$B=\frac{(1.256\cdot 10^{-7} H/m)(6.5 A)}{2 \pi (0.063 m)}=2.1\cdot 10^{-6} T=2.1 \mu T$