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Arlecino [84]
3 years ago
11

A transport plane takes off from a level landing field with two gliders in tow, one behind the other. The mass of each glider is

700 kg, and the total resistance (air drag plus friction with the runway) on each may be assumed constant and equal to 4300 N. The tension in the towrope between the transport plane and the first glider is not to exceed 12000 N.
If a speed of 40 m/s is required for takeoff, what minimum length of runway is needed?
Physics
1 answer:
Rom4ik [11]3 years ago
6 0

Answer:

Length = 155.6 m

Explanation:

given data

mass = 700 kg

total resistance = 4300 N

tension = 12000 N

speed = 40 m/s

solution

we get here equation for glider in the back  and front  

for the glider in the back

T - 2400 = 700 a    ...........1

for the glider in front

12000 - T - 2400 = 700a    .............2

now we add both  these equations

12000 - 4800 = 1400 a     .............3

a = 5.14 m/s²

and

now we use equation of motion

v² - u² = 2 a S    .............4

40² = 2 × 5.14 × S

so  

Length = 155.6 m

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By the conservation of momentum principle and assuming there is no external force (e.g. friction) acting on the system, the total initial momentum is equal to the total final momentum.

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Equating both initial and final total momenta,

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</span><span>It should be noted that the angle needs be halved because we are only concerned with the angle between m=1 and m=0 and they gave you the angle between m=1 to the right of the center and m=1 on the left of the center. We calculate as follows:
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