Please help me with the answer!!!

masha68 [24]

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - given point

$\bullet\ (2,\ 7),\ m=-4\\\\y-7=-4(x-2)\\\\\bullet(-6,\ -2),\ m=3\\\\y-(-2)=3(x-(-6))\to y+2=3(x+6)\\\\\bullet(12,\ 5),\ m=-3\\\\y-5=-3(x-12)\\\\\bullet(7,\ -6),\ m=\dfrac{1}{2}\\\\y-(-6)=\dfrac{1}{2}(x-7)\to y+6=\dfrac{1}{2}(x-7)\\\\\bullet(4,\ -5),\ m=6\\\\y-(-5)=6(x-4)\to y=y+5=6(x-4)\\\\\bullet(-8,\ 2),\ m=-\dfrac{3}{4}\\\\y-2=-\dfrac{3}{4}(x-(-8))\to y-2=-\dfrac{3}{4}(x+8)$

8 0

3 years ago

Solve: a.x3+x2-8x - 12x+2 b. x3-4x2-3x + 18x-3 c. x2 + 4x + 4 d. x2 - 6x + 9

NeTakaya

<h2>Steps:</h2>

So firstly, this function is asking us to divide f(x) by g(x) so let's set that up as such:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\div \frac{x-3}{x+2}$

Next, remember that dividing by a number is the same as multiplying by its reciprocal. To find the reciprocal of a number, flip the numerator and denominator around. With this info, flip the second fraction to it's reciprocal and change the sign to multiplication:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\times \frac{x+2}{x-3}$

Next, we are going to factor x² - x - 6. Firstly, what two terms have a product of -6x² and a sum of -x? That would be -3x and 2x. Replace -x with 2x - 3x:

$(\frac{f}{g})(x)=\frac{x^2+2x-3x-6}{1}\times \frac{x+2}{x-3}$

Next, factor x² + 2x and -3x - 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

$(\frac{f}{g})(x)=\frac{x(x+2)-3(x+2)}{1}\times \frac{x+2}{x-3}$

Now you can rewrite it as:

$(\frac{f}{g})(x)=\frac{(x-3)(x+2)}{1}\times \frac{x+2}{x-3}$

Next, multiply:

$(\frac{f}{g})(x)=\frac{(x-3)(x+2)^2}{x-3}$

Next, divide:

$(\frac{f}{g})(x)=(x+2)^2$

And lastly, simplify:

A good tip: $(x+y)^2=x^2+2xy+y^2$

$(\frac{f}{g})(x)=x^2+4x+4$

<h2>Answer:</h2>

The correct option is C. x² + 4x + 4.

7 0

3 years ago

Please help i don't even where to start solve for x

aliina [53]

The radius is 10, so the diameter is 20. This means the parts of the diameter (the chord through the center P) to the left and right of the vertical chord have lengths 16 and 4, respectively.

Because the horizontal chord is a diameter, the vertical chord is cut in half, so its parts above and below the diameter both have length x.

Now, by the intersecting chord theorem,

16×4 = x × x

or

x ² = 64

so that

x = 8

6 0

3 years ago

Solve sec2theta + tantheta - 3 =0 for 0

Serhud [2]

Answer:

Ф = $\frac{\pi }{4} ,\frac{5\pi}{4}$

Step-by-step explanation:

It is a bit difficult to input the work here, so I uploaded an image

First we can use the trig identities to change sec²(Ф) to tan²(Ф) + 1
Then we can combine like terms
Then we can factor this as a polynomial function
Then we can set each term equal to zero and solve for Ф
The first term tan(Ф) - 2 = 0 has no solution because tan(Ф) ≠ -2 anywhere
The second term tan(Ф) - 1 = 0 has two solutions of $\frac{\pi}{4}$ and $\frac{5\pi}{4}$ so these are the solutions to the problem