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shutvik [7]
3 years ago
15

Please help me with the answer!!!

Mathematics
1 answer:
docker41 [41]3 years ago
8 0

5x = 7x - 8

7x - 5x = 8

2x = 8

x = 8 ÷ 2

x = 4

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A research study investigated differences between male and female students. Based on the study results, we can assume the popula
garri49 [273]

Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of \mu = 3.5.
  • The standard deviation is of \sigma = 0.5.
  • Sample of 100, hence n = 100, s = \frac{0.5}{\sqrt{100}} = 0.05

The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-2 = \frac{X - 3.5}{0.05}

X - 3.5 = -0.1

X = 3.4

Z = 2:

Z = \frac{X - \mu}{s}

2 = \frac{X - 3.5}{0.05}

X - 3.5 = 0.1

X = 3.6

The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

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Convert 7.5 to a decimal
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7.5 is already in decimal form.

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Answer:

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*-This is all in my on words-*

(Hope this helps)

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Use the following work shown below to answer the following question.​
zysi [14]

Answer:

\frac{3 + \sqrt{3x} }{3 - x}

Step-by-step explanation:

You can use the work they gave you and continue from there:

\frac{\sqrt{3}(\sqrt{3}) + \sqrt{3}(\sqrt{x})  }{(\sqrt{3}) ^{2} - (\sqrt{x} )^{2} }

First, simplify the numerator:

\frac{3 + \sqrt{3x} }{(\sqrt{3}) ^{2} - (\sqrt{x}) ^{2} }

Finally, simplify the denominator:

\frac{3 + \sqrt{3x} }{3 - x}

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