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Anna71 [15]
2 years ago
9

I need help figuring out the first step would it be adding up the like terms? help

Mathematics
1 answer:
Pie2 years ago
6 0

Answer: Add like terms

Step-by-step explanation:

For example, you would add 6x and 5x to make 11x, but there other two numbers you would leave alone.

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Find the factors that multiply to give you -42 and add to give you -1.
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-7 and positive 6. if you multiply a negative by a positive it will always be a negative.
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3 years ago
which are the roots of the quadratic function f(b) = b2 – 75? check all that apply. b = 5 square root of 3 b = -5 square root of
malfutka [58]
<span>The answers are b = 5 square root of 3; b = -5 square root of 3. f(b) = b^2 – 75. If f(b) = 0, then b^2 – 75 ) 0. b^2 = 75. b = √75. b = √(25 * 3). b = √25 * √3. b = √(5^2) * √3. Since √x is either -x or x, then √25 = √(5^2) is either -5 or 5. Therefore. b = -5√3 or b = 5√3.</span>
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3 years ago
Read 2 more answers
What Is The Prime Factor Of 4275 ?
jarptica [38.1K]

Answer:

5^2·3^2·19

Step-by-step explanation:

Well to find the prime factor we make the prime factorization tree.

Look at the image below↓

<em>Thus,</em>

<em>the prime factorization of 4275 is </em>5^2·3^2·19

<em>Hope this helps :)</em>

4 0
3 years ago
The cost of Samantha's 15th birthday party depends on the number guest. The hall charges $250 for the use of the hall plus $12 p
Scorpion4ik [409]

Answer:

Equation: y=x(12)+250

Total cost: $550

3 0
3 years ago
Select all the expressions equivalent to: (4^5)⋅4^3 Group of answer choice 2^14 4^12 2^16 16^8 4^8 16^4
kumpel [21]

Answer:

Choices given as 2^{16}, 4^8 and 16^4 are correct.

Step-by-step explanation:

Given expression is,

(4^5)(4^3)

By applying law of exponents in the given expression,

(4^5)(4^3)=4^{5+3}

            =4^8

(4^5)(4^3)=(2^2)^5(2^2)^3

            =(2^{2\times 5})(2^{2\times 3})

            =2^{10}\times 2^6  

            =2^{16}

            =(2^4)^4

            =(16)^4

Therefore, choices given as 2^{16}, 4^8 and 16^4 are correct.

4 0
3 years ago
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