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3 years ago

14

WILL GIVE BRAILLEST IF YOU HELP ME!

1 answer:

Jlenok [28]3 years ago

5 0

Answer:

3 centimeters per minute so solving the equation 15 divided by 4 for the y value equal to 30

Step-by-step explanation:

BRAINLIEST PLEASE

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The graph below shows the height of a kicked soccer ball f(x), in feet, depending on the distance from the kicker x, in feet: Pa

Lapatulllka [165]

Answers are 55, and 103
hope i helped

8 0

3 years ago

What's the answer for this problem number 6 and how did you get your answer?

lorasvet [3.4K]

$\frac{7}{b + 5} = \frac{10}{5} \\$

$\frac{7}{b + 5} = 2 \\$

Multiply the sides of the equation by ( b + 5 ) :

$7 =2 \times (b + 5)$

$7 = 2b + 10$

Subtract the sides of the equation minus 10 :

$7 - 10 = 2b$

$- 3 = 2b$

Divided the sides of the equation by 2 :

$b = - \frac{3}{2} \\$

____________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

4 0

4 years ago

several years ago wolves were reintroduced in to a national park in north carolina in north carolina. Researchers have monitored

kicyunya [14]

Answer: $5766.503\ \text{wolves}$

Step-by-step explanation:

Given

Current Population of wolves is $P_o=100$

If the growth rate is $=0.5$

So the population in next year is

$P_1=100+100\times 0.5$

$P_1=100(1+0.5)$

similarly $P_2=100(1+0.5)^2$

So population after n years is $P_n=P_o(1+r)^n$

Population after 10 years is

$P_{10}=100(1+0.5)^{10}$

$P_{10}=5766.503\ \text{wolves}$

3 0

3 years ago

Find two positive numbers satisfying the given requirements. The product is 216 and the sum is a minimum. (No Response) (smaller

fgiga [73]

Answer:

$x1=\sqrt{216} \ and \ y1=\ \sqrt{216}$

Step-by-step explanation:

Let the first number is x1 and other number is y1 then

$x1 * y1 =216$

Therefore

$y1=$ $\frac{216}{x1}$

also there sum is

$s1 =x1+y1$ ....Eq(1)

Putting the value of y1 in the previous equation

$s1\ =x1 + \frac{216}{x1}$ ........Eq(2)

Differentiate the the Eq(2) with respect to x1 we get

$\frac{ds1}{dx1} \ =\ 1+216*\frac{1}{-x1^{2} }$

$\frac{ds1}{dx1} \ =\ 1-\frac{216}{x1^{2} }\ =\ 0$

${x1^{2} }\ =\ 216\\ x1=\sqrt{216}$

Putting the value of X1 in Eq(1) we get

$y1=\frac{216}{\sqrt{216} } \\y1=\frac{216*\sqrt{216} }{216} \\y1=\ \sqrt{216}$

So $x1=\sqrt{216} \ and \ y1=\ \sqrt{216}$

6 0

4 years ago

Can someone help me with these 3

photoshop1234 [79]

24. 244 cm

25. 65 mm

26. 37/80 or 0.4625

8 0

4 years ago