Holly cuts 2 ribbons into tenths for a craft project how many 1/10 size ribbons does she have

Mathematics

1 answer:

boyakko [2]2 years ago

6 0

Answer:

Holly would have 20 1/10 sized ribbons.

Step-by-step explanation:

One whole ribbon would equal out to 10, this number multiplied by 2 would be 20. Therefore meaning she should have 20 1/10 sized pieces of ribbon.

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X² + y² if x = 7 and y = 5. What is the solution to this??

Shtirlitz [24]

Hey there!

x^2 + y^2

= 7^2 + 5^2

= 7 * 7 + 5 * 5

= 49 + 25

= 74

Therefore, your answer should be: 74

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

3 0

1 year ago

Read 2 more answers

Tell whether the ordered pair is a solution of the given system. (-2,-4) {y=1/2x -3, y=-2x-8}

kompoz [17]

Answer:

The ordered pair $(-2,\, -4)$ is indeed a solution to the system:

$\left\lbrace\begin{aligned} & y = \frac{1}{2}\, x - 3 \\ & y = -2\, x - 8\end{aligned}\right.$ .

Step-by-step explanation:

Consider a system of equations about variables $x$ and $y$ . An ordered pair $(x_{0},\, y_{0})$ (where $x_{0}$ and $y_{0}$ are constant) is a solution to that system if and only if all equations in that system hold after substituting in $x = x_{0}$ and $y = y_{0}$ .

For the system in this question, $(-2,\, -4)$ would be a solution only if both equations in the system hold after replacing all $x$ in equations of the system with $(-2)$ and all $y$ with $(-4)$ .

The $\texttt{LHS}$ of the equation $y = (1/2)\, x - 3$ would become $(-4)$ . The $\texttt{RHS}$ of that equation would become $(1/2) \, (-2) - 3$ . The two sides are indeed equal.

Similarly, the $\texttt{LHS}$ of the equation $y = -2\, x - 8$ would become $(-4)$ . The $\texttt{RHS}$ of that equation would become $(-2)\, (-2) - 8$ . The two sides are indeed equal.

Thus, $x = (-2)$ and $y = (-4)$ simultaneously satisfy both equations of the given system. Therefore, the ordered pair $(-2,\, -4)$ would indeed be a solution to that system.