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Olin [163]
3 years ago
8

Which is the graph of the line LaTeX: y-2=3\left(x-1\right)y − 2 = 3 ( x − 1 )?

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

D.

Step-by-step explanation:

The equation given takes the point-slope form which is, y - b = m(x - a). Where,

(a, b) = (x, y) coordinates of a point on the line.

m = slope of the line .

To find which graph has a line equation of y - 2 = 3(x - 1), look for the points which will give you something almost exactly as the equation if you substitute their values into y - b = m(x - a).

Let's consider option D.

We have a given point (1, 2). a = 1, b = 2.

Substitute these into y - b = m(x - a)

We have:

y - (2) = m(x - (1))

y - 2 = m(x - 1)

As you can see, this looks almost exactly as

y - 2 = 3(x - 1).

If you want to be certain that option D is the answer, find m by using the coordinates of any other point on the line and plug into y - 2 = m(x - 1) to find m:

In graph D, let's take the points (0, -1)

-1 - 2 = m(0 - 1)

-3 = m(-1)

-3 = -m

Divide both sides by -1

3 = m

m = 3.

Therefore, option D is the graph of the line y - 2 = 3(x - 1).

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Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

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Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

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