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blagie [28]
3 years ago
13

How do I solve 8d3 + (6d2 – 4d)

Mathematics
2 answers:
motikmotik3 years ago
8 0
I guess you want to factor this.
the greatest common factor is 2d so we can write:-
= 2d(4d^2 + 3d - 2)
kompoz [17]3 years ago
5 0
<span>8d3 + (6d2 – 4d)
=</span><span>8d3 + 6d2 – 4d
=2d(4d^2 + 3d - 2)
=2d(2d - 1)(d + 2) ...simplify and this is your answer

</span>
You might be interested in
When x=1/2, what is the value of 8x-3 over x?
Taya2010 [7]

\frac{8( \frac{1}{2}) - 3 } { \frac{1}{2} }
\frac{(8 \times \frac{1}{2}) - 3 }{ \frac{1}{2} }  =  \frac{4 - 3}{ \frac{1}{2} }
Because half of 8 is 4

\frac{1}{ \frac{1}{2} }  =  \frac{1 \times 2}{1 \times 1} = 2
Divide 1 by 1/2 or .5... 1 becomes 1/1 and 1/2 is flipped to 2/1, then multiply
5 0
3 years ago
I need the answer please help me
Anna71 [15]

Answer:

-29.988 or if you round up -30

Step-by-step explanation:

1) Convert fractions to decimals  

    3.6 x (-8.33) = -29.988

4 0
2 years ago
Read 2 more answers
What are the vertex, axis of symmetry, domain and range of the function:
DiKsa [7]
Y=(-x*x)-4x+3
y=-(x^2+4x-3)
4+y=-(x^2+4x+4)+3
y+4=-(x-2)^2.) +3
-4. -4
y=-((x-2)^2)-1

Answers:
Vertex: (2,-1)
AOS:x = 2
Domain: All Real Numbers
Range:[-1,Infinity)
3 0
3 years ago
Renee uses 12 marshmallows and 8 graham crackers to make 4 s'mores. Drag marshmallows and graham crackers into the box to show h
Anit [1.1K]
To find out how much is needed for 1 you will need to divide each given value by 4:
12 marshmallows / 4 = 3
8 graham crackers / 4 = 2
4 smores / 4 = 1
you then need to multiply each value by 3 :
3 marshmallows x 3 = 9
2 graham crackers x 3 = 6
1 smore x 3 = 3
therefore the answer would be :
9 marshmallows
6 graham crackers

hope this helps you


7 0
3 years ago
Read 2 more answers
⦁ Evaluate ⦁ 6! ⦁ 8P5 ⦁ 12C4
lisabon 2012 [21]
6! = 6 * 5 *4*3*2*1 =720

8p5 = 8*7*6*5*4 = 6720

12C4 = (12p4)/4! = (12*11*10*9)/4*3*2*1 = 495
7 0
3 years ago
Read 2 more answers
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