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statuscvo [17]
3 years ago
15

Please help. Math - geometric

Mathematics
1 answer:
neonofarm [45]3 years ago
8 0

Answer:

FIRST option

Step-by-step explanation:

mark me brainlist btw help my sum plsss

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HELP!!!
Oliga [24]

Answer:

i think is 26 i may be wrong tho

8 0
3 years ago
What phrase best describes a rhombus
jolli1 [7]
B should be the answer but don't hold that to me. I say B because a rhombus only has two parallel sides which are the top and bottom lines. 
8 0
3 years ago
Find the range of the given function f(x)=(x-1)^2+1
alexgriva [62]

Answer:

  a.)  [1, infinity)

Step-by-step explanation:

The equation is that of a parabola that opens upward with vertex (1, 1). Hence the minimum value of f(x) is 1, and all values greater than that are part of the range: [1, ∞).

_____

The "vertex form" of the equation of a parabola is ...

  f(x) = a(x -h)^2 + k

The vertex is at (h, k). When a > 0, the parabola opens upward. When a < 0, the parabola opens downward. Whichever way it opens, the value k is an extreme value and the limit of the range.

5 0
4 years ago
the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
HELP PLEASE WHATS NOT A FUNCTION
Galina-37 [17]
Answer
D
Why?
Because one of the x value is used twice
8 0
3 years ago
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