Answer:
Circle or pie graph is used to show how a part of something relates to the whole.
Explanation:
Pie graphs are easy to read and can present a very clear picture of the relationships.
Answer: 45 A
Explanation:
Primary only protection 3-phase
I = 3 phase kVA / ( 1.723 * V)
I = 30000 / ( 1.732 * 480 ) = 36.085 A
Table 450.3(B)
Currents of 9A or more column
primary only protection = 125%
Max OCPD pri = 125% of I = 1.25 * 36.085 = 45.11 A
Table 450.3(B) Note 1 does not apply, use next smaller Table 240.6(A)
Next smaller = 45 A
Answer:
I = 0.15 A
Explanation:
The question is "a lamp subjected to a continuous voltage of 12V , consumes a power of 1.8 W. The intensity of the current passing through the lamp is what"
Given that,
Power of the lamp, P = 1.8 W
Voltage, V = 12 V
We need to find the current through the lamp. The power of the lamp is given by :

So, the current through the lamp is 0.15 A.
Answer:
The pressure of the water in the pipe is 129554 Pa.
Explanation:
<em>There are wrongly written values on the proposal, the atmospheric pressure must be 101105 Pa, and the density of water 1001.03 kg/m3, those values are the ones that make sense with the known ones.</em>
We start usign the continuity equation, and always considering point 1 a point inside the pipe and point 2 a point in the nozzle:

We want
, and take into account that the areas are circular:

Substituting values we have (we don't need to convert the cm because they cancel out between them anyway):

For determining the absolute pressure of the water in the pipe we use the Bernoulli equation:

Since the tube is horizontal
and those terms cancel out, so the pressure of the water in the pipe will be:

And substituting for the values we have, considering the pressure in the nozzle is the atmosphere pressure since it is exposed to it we obtain:
